Answer:
x^2 y^12
Step-by-step explanation:
( x ^ 1/2 * y ^3 ) ^ 4
A power raised to a power has the exponents multiplied
a^b^c = a^ (b*c)
x^ 1/2 ^ 4 * y^3^4
x^(1/2*4) * y^(3*4)
x^2 y^12
<u>Answer:</u>
are two roots of equation 
<u>Solution:</u>
Need to solve given equation using quadratic formula.
General form of quadratic equation is 
And quadratic formula for getting roots of quadratic equation is
In our case b = -1 , a = -3 and c = -3
Calculating roots of the equation we get
Since 
is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.
The symmetry line is passing through points F and E. Then the correct option is B.
<h3>What is reflectional symmetry?</h3>
Consider a plane. Consider a design or shape on that plane. Now consider an axis.
If we think of that axis as a mirror, and on the opposite side of that axis create the image of the considered shape, then if the shape's image looks exactly like the shape itself, then that shape is called to have reflectional symmetry.
Then the symmetry line is passing through points F and E. Because F and E are the mid-points of AD and BC.
Learn more about symmetry here:
brainly.com/question/7783612
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