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sweet-ann [11.9K]
2 years ago
15

Raman and Raj go for a party each having Rs. 100, If they decide to expend Rs. 150, Then in how many ways they can make the paym

ent​
Mathematics
1 answer:
Oduvanchick [21]2 years ago
8 0

Answer:

only 1 way

Step-by-step explanation:

both of them give their Rs.100 so now it's Rs.200 so pay RS 200 and they'll get Rs 50 as the remain

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Solve using elimination.<br><br> 8x − 7y = –5<br> –x + 4y = –15
xz_007 [3.2K]
Steps
8x−7y=−5
Add 7y to both sides
8x−7y+7y=−5+7y
Simplify
8x=−5+7y
Divide both sides by 8
8x
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Simplify
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2 years ago
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John went to the grocery store and purchased cans of soup and frozen dinners. Each can of soup has 150 mg of sodium and each fro
Fantom [35]

Answer:

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Step-by-step explanation:

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3 years ago
What is the length of the missing leg <br> 15 and 9 meters
Brilliant_brown [7]

Answer: 12

Step-by-step explanation: I assume you are talking about a triangle in which the Hypotenuse is 15 and leg A is 9

in this case we have to use a reverse pythagorean theorem

the original one is a^ + b^ = c^ then reverse it to get c^ - a ^ = b^

we know that C is 15 and A is 9 so substitute

15^ - 9^ = b^

15 ^ = 225 and 9^ = 81 so substitute again

225 - 81 = b^ then subtract

144 = b^  you know that the square root of 144 is 12 because 12 x 12 = 144

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4 0
3 years ago
Find the volume of a ball with a radius of 7cm.
vichka [17]

Answer:

Use the formula V = 4/3pi r^3

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Step-by-step explanation:

6 0
2 years ago
Compare the investment below to an investment of the same principal at the same rate compounded annually.
Andrews [41]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus twice} \end{array}\dotfill &2\\ t=years\dotfill &19 \end{cases} \\\\\\ A=5000\left(1+\frac{0.08}{2}\right)^{2\cdot 19}\implies A\approx 22194.067 \\\\[-0.35em] ~\dotfill

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &19 \end{cases} \\\\\\ A=5000\left(1+\frac{0.08}{1}\right)^{1\cdot 19}\implies A\approx 21578.505

6 0
2 years ago
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