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aleksandrvk [35]
3 years ago
8

Write the place and value of the digit 3 in each number 3,476 384,400 5,437,200,184,400

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
6 0
1. thousands place value 3000
2. 3 hundred thousand value 300,000
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X-y+z=-4<br><br> 3x+2y-z=5<br><br> -2x+3y-z=15<br><br> How do I solve this?
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1)\ \ \ x-y+z=-4\ \ \ \Rightarrow\ \ \ z=-4-x+y\\\\2)\ \ \ 3x+2y-z=5 \\.\ \ \ \  \Rightarrow\ \ 3x+2y-(-4-x+y)=5 \\.\ \ \ \  \Rightarrow\ \ 3x+2y+4+x-y=5 \\.\ \ \ \  \Rightarrow\ \ 4x+y=1\\\\3)\ \ \ -2x+3y-z=15\\.\ \ \ \  \Rightarrow\ \ -2x+3y-(-4-x+y)=15\\.\ \ \ \  \Rightarrow\ \ -2x+3y+4+x-y=15\\.\ \ \ \  \Rightarrow\ \ -x+2y=11\\--------------------\\

z=-4-x+y\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ and\\ \left \{ {{4x+y=1\ \ \ \ } \atop {-x+2y=11\ /\cdot4}} \right. \\\\\left \{ {{4x+y=1\ \ \ \ } \atop {-4x+8y=44}} \right. \\-------\\y+8y=1+44\\9y=45\ /:9\\y=5\\\\-x+2y=11\ \ \ \Rightarrow\ \ \ x=2y-11\ \ \ \Rightarrow\ \ \ x=2\cdot5-11=-1\\\\z=-4-x+y=-4-(-1)+5=-4+1+5=2\\\\Ans.\ x=-1\ \ \ and\ \ \ y=5\ \ \ and\ \ \ z=2
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3 years ago
The second fret is 33.641 mm from the first fret. The third fret is 31.749 mm from the second fret. How far is the third fret fr
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Step-by-step explanation:

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3y+10x−54=0<br> 5y−2x−34=0<br> ​
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Step-by-step explanation:

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Add. Write your answer in simplest form.
AleksAgata [21]

Answer: B. 1 7/36

Hope that helped! :)

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3 years ago
What is the simplified value of the expression below?
slavikrds [6]

Answer:

I dont know the experssion but I will give you steps to figure it out!

Step-by-step explanation:

Before you evaluate an algebraic expression, you need to simplify it. This will make all your calculations much easier. Here are the basic steps to follow to simplify an algebraic expression:

remove parentheses by multiplying factors

use exponent rules to remove parentheses in terms with exponents

combine like terms by adding coefficients

combine the constants

When simplifying an expression, the first thing to look for is whether you can clear any parentheses. Often, you can use the distributive property to clear parentheses, by multiplying the factors times the terms inside the parentheses. In this expression, we can use the distributive property to get rid of the first two sets of parentheses.

Now we can get rid of the parentheses in the term with the exponents by using the exponent rules we learned earlier. When a term with an exponent is raised to a power, we multiply the exponents For example, (x2)2 becomes x4.

The next step in simplifying is to look for like terms and combine them. The terms 5x and 15x are like terms, because they have the same variable raised to the same power

Finally, we look for any constants that we can combine.

Now our expression is simplified. Just one more thing -- usually we write an algebraic expression in a certain order. We start with the terms that have the largest exponents and work our way down to the constants. Using the commutative property of addition, we can rearrange the terms and put this expression in correct order, like this.

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