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Tomtit [17]
3 years ago
10

What is the explicit rule for the sequence? 10.5, 9, 7.5, 6, 4.5, 3, ...

Mathematics
1 answer:
makvit [3.9K]3 years ago
6 0
Answer: the rule is to add 1.5

3 + 1.5 = 4.5
4.5 + 1.5 = 6
6 + 1.5 = 7.5
etc...
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In the equation 0.75s-5/8 = 44, how do you combine the like terms?
garri49 [273]

Answer:

Step-by-step explanation:

In the given equation, the "like terms" are the constants 5/8 and 44.

It simplifies the math if we eliminate the fractions first.  Note that 0.75 = 6/8, so now we have:

8(6/8)s - 8(5/8) = 44).

Multiplying all three terms by 8 (above) yields

8(6s) - 8(5) = 8(44), or

48s              = 8(44 + 5), or 48s = 8(49)

Dividing both sides by 48 yields s:   s = 8(49/48)

Review "like terms:"  These are terms that have at least one characteristic in common.  5/8 and 44 are like terms because they are only constants (no variables are present).  We must add 5/8 and 44.   0.75s does not have a "like term" in the given equation.

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Which expression is equivalent to the expression below? StartFraction 6 c squared 3 c Over negative 4 c 2 EndFraction divided by
Fudgin [204]

The given equation (6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2) is equivalent to the expression -3c.

Given that, the expression can be written as.

(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)

By simplifying the above equation,

\dfrac{6c^2+3c}{-4c+2}\div \dfrac{2c+1}{4c-2}

By taking out the common terms from the equation,

\dfrac{3c(2c+1)}{2(-2c+1)}\div\dfrac{2c+1}{2(2c-1)}

By simplifying the above equation by cancel out the common factors.

\dfrac{3c}{-2c+1} \div \dfrac{1}{2c-1}

Now, by taking (-1) common from (-2c+1) we get,

\dfrac{3c}{-1(2c-1)} \div \dfrac{1}{2c-1}

By simplifying the above equation, we get the expression,

-3c

So the given equation (6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2) is equivalent to the expression -3c.

For more details, follow the link given below.

brainly.com/question/1301963.

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