You already know what it is cuh
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Answer: 5</h3>
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Explanation:
Let's consider the expression (x-y)^2. It expands out to x^2-2xy+y^2. The terms are:
Each of those terms either has a single variable with an exponent of 2, or has the exponents add to 2. Think of 2xy as 2x^1y^1.
In short, this means that the degree of each monomial term is 2.
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Now consider (x-y)^3. It expands out into x^3-3x^2y+3xy^2+y^3.
We have terms that either have a single variable and the exponent is 3, or the exponents add to 3. The degree of each term is 3.
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This pattern continues.
In general, for (x-y)^n, where n is any positive whole number, the degree of each term in the expansion is n. If you picked any term, added the exponents, then the exponents will add to n.
Here ya go
Math.way is the way to go ^v^
Hope ya have a good one
The order of operations tells you exponentiation is done before multiplication or addition. That is, the value of x is squared before the sign is applied.
Your result will be negative for any non-zero value of x.
Trinomial 2x² + 4x + 4.
It's of the form ax²+bx+c and it's discriminant is Δ=b² - 4.a.c
(in our case Δ = 4² - (4)(2)(4) → Δ = - 32
We know that: x' = -1 + i and x" = -1 - i
If Δ > 0 we have 2 rational solutions x' and x"
If Δ = 0 we have1 rational solution x' = x"
If Δ < 0 we have 2 complex solutions x' and x", that are conjugate
In our example we have Δ = - 16 then <0 so we have 2 complex solutions
That are x'= [-b+√Δ]/2.a and x" = [-b-√Δ]/2.a
x' =
