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3 years ago

This question is based on the following circle graph.

Mathematics

2 answers:

Law Incorporation [45]3 years ago

6 0

Answer: D. 76

Step-by-step explanation:

Since, the total number of people = 400,

By the given diagram,

The percentage of the number of people who prefer to watch WWCN = 41 %

⇒ The number of people who prefer to watch WWCN = 41% of 400 = 0.41 × 400 = 164

Now, The percentage of the number of people who prefer to watch WANR = 22 %

⇒ The number of people who prefer to watch WANR = 22% of 400 = 0.22 × 400 = 88

Thus, the difference between the number of people who prefer WWCN and WANR = 164 - 88 = 76

⇒ Option D is correct.

Pepsi [2]3 years ago

3 0

41% of 400 is 164 22% of 400 is 88 164-88=76 hope this helps

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lina2011 [118]

Answer:

1) The equation that represents the number of slices of bacon to the number he will eat, assuming he eats 24 grams is;

3·x + 6·y = 24

2) The equation in slope and intercept form is;

y = 4 - 0.5·x

Step-by-step explanation:

1) The given parameters are;

The amount of protein Tommy wants to eat for breakfast = 24 grams

The quantity of protein in a slice of bacon = 3 grams

The quantity of protein in an egg = 6 grams

Let x represent the number of slices of bacon he will eat and let y represent the number of eggs he will eat

The equation that represents the number of slices of bacon to the number he will eat, assuming he eats 24 grams is given as follows;

3·x + 6·y = 24

2) The equation in slope and intercept form is given by making y the subject of the above equation as follows;

3·x + 6·y = 24

6·y = 24 - 3·x

y = 24/6 -1/2·x

y = 4 - 0.5·x, which is in the slope and intercept form y = m·x + c

Where;

m = The slope = -0.5

c = The y-intercept = 4

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3 years ago

Factor completely: 4x2 + 25x + 6

steposvetlana [31]

(x + 6)(4x + 1) 
x times 4x = 4x^2 
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6 times 1 = 6 
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Write the equation of the line that passes through the point(-6,12) and is parallel to the line y=8

Ugo [173]

Answer:

y = 12

Step-by-step explanation:

y = 8 is the equation of a horizontal line, parallel to the x- axis.

Thus a parallel line will also be horizontal.

The equation of a horizontal line is

y = c

where c is the y- coordinates of the points it passes through.

The line passes through (- 6, 12) with y- coordinate of 12, thus

y = 12 ← equation of parallel line

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3 years ago

Please help? I’m super lost...

babunello [35]

Answer:

Step-by-step explanation:

In all of these problems, the key is to remember that you can undo a trig function by taking the inverse of that function. Watch and see.

a. $sin2\theta =-\frac{\sqrt{3} }{2}$

Take the inverse sin of both sides. When you do that, you are left with just 2theta on the left. That's why you do this.

$sin^{-1}(sin2\theta)=sin^{-1}(-\frac{\sqrt{3} }{2} )$

This simplifies to

$2\theta=sin^{-1}(-\frac{\sqrt{3} }{2} )$

We look to the unit circle to see which values of theta give us a sin of -square root of 3 over 2. Those are:

$2\theta =\frac{5\pi }{6}$ and

$2\theta=\frac{7\pi }{6}$

Divide both sides by 2 in both of those equations to get that values of theta are:

$\theta=\frac{5\pi }{12},\frac{7\pi }{12}$

b. $tan(7a)=1$

Take the inverse tangent of both sides:

$tan^{-1}(tan(7a))=tan^{-1}(1)$

Taking the inverse tangent of the tangent on the left leaves us with just 7a. This simplifies to

$7a=tan^{-1}(1)$

We look to the unit circle to find which values of a give us a tangent of 1. They are:

$7\alpha =\frac{5\pi }{4},7\alpha =\frac{\pi }{4}$

Dibide each of those equations by 7 to find that the values of alpha are:

$\alpha =\frac{5\pi}{28},\frac{\pi}{28}$

c. $cos(3\beta)=\frac{1}{2}$

Take the inverse cosine of each side. The inverse cosine and cosine undo each other, leaving us with just 3beta on the left, just like in the previous problems. That simplifies to:

$3\beta=cos^{-1}(\frac{1}{2})$

We look to the unit circle to find the values of beta that give us the cosine of 1/2 and those are:

$3\beta =\frac{\pi}{6},3\beta =\frac{5\pi}{6}$

Divide each of those by 3 to find the values of beta are:

$\beta =\frac{\pi }{18} ,\frac{5\pi}{18}$

d. $sec3\alpha =-2$

Let's rewrite this in terms of a trig ratio that we are a bit more familiar with:

$\frac{1}{cos(3\alpha) } =\frac{-2}{1}$

We are going to simplify this even further by flipping both fraction upside down to make it easier to solve:

$cos(3\alpha)=-\frac{1}{2}$

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$3\alpha =cos^{-1}(-\frac{1}{2} )$

We look to the unit circle one last time to find the values of alpha that give us a cosine of -1/2:

$3\alpha =\frac{7\pi}{6},3\alpha =\frac{11\pi}{6}$

Dividing both of those equations by 3 gives us

$\alpha =\frac{7\pi}{18},\frac{11\pi}{18}$

And we're done!!!

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