The bearing of the individuals from each other are as indicated below;
- S45°E
- N25°E
- S65°E
- S15°E
- N45°E
- N75°E
<h3>What is bearing of Henley from Dinder?</h3>
It follows from the task content that the bearing of the individuals from each other are expected to be determined.
a) For Henley from Dinder; it follows from observation that Henley is; S45°E of Dinder's position.
b) For Dinder from Weare; it follows from observation that Dinder is; N25°E of Weare's position.
c) For Weare from Dinder; it follows from observation that Weare is; S65°E of Dinder's position.
d) For Weare from Henly; it follows from observation that Weare is; S15°E of Dinder's position.
e) For Dinder from Henly; it follows from observation that Dinder is; N45°E of Henly's position.
f) For Henly from Weare; it follows from observation that Henly is; N75°E of Weare's position.
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Answer: w= -10
Step-by-step explanation: move all terms not containing w to the right side of the equation
Answer:
Step-by-step explanation:
Let B be the number of black cars and S the number of silver.
We know that B/S = 7/4
We also know that B - S = 12
Rearrange the first: B = 7S/4
B - S = 12
7S/4 - S = 12
7S - 4S = 48
3S = 48
S = 16
B/S = 7/4
B/16 = 7/4
4B = 112
B = 28
B + S = 44 cars
I can't add the tape diagram here, but show two ribbons (tapes) for each car color and drawn so one can see the relative numbers of each.
Answer:
4= -5v-1
5= 3x
6= 9y-6
7= h-20
8= 29w-17z
9= 8mn-2n+5m
Step-by-step explanation:
first three that you did were correct! Hope it helps!
