Answer: 3024 ways
Step-by-step explanation: 9*8*7*6*5=3024
Answer:
Step-by-step explanation:
<u><em>The correct question is</em></u>
Translate the sentence into an equation using n as the unknown number. Then solve the equation for n.
5 increased by half a number is 11
Let
n ----> the unknown number
we know that
The linear equation that represent this situation is
solve for n
Multiply by 2 both sides
subtract 10 both sides
The perimeter is 6x + 12, and a model example is attached.
All three sides of an equilateral triangle are the same, so multiply the side length by 3 to find the perimeter.
3(2x + 4)
Now distribute the 3.
3 * 2x + 3 * 4
6x + 12
The average value of the given function is .
According to the statement
we have given that the function f(x) and we have to find the average value of that function.
So, For this purpose, we know that the
The given function f(x) is
And now integrate this function with the limit 0 to a then
Now integrate this then
Then the value becomes according to the integration rules is:
Now put the limits then answer will become as output is:
Now solve this equation then
Now
This is the value which represent the average of the given function in the statement.
So, The average value of the given function is .
Learn more about integration here
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Make a table with the angle theta as independent variable and the radius r as dependent variable:
theta radius = 4+2cos theta radius
------- -----------------------------------------
0 4+2 6
pi/6 4+2cos pi/6 = 4+2(sqrt(3)/2
Perhaps you have already plotted this using webassign (but remember that you have not shared an illustration here). (Please don't type "webassign plot" repeatedly, as it accomplishes nothing.)
Generally, when one wishes to find the area of a region defined by polar functions (as is the case here), one first determines suitable limits of integration from the finished curve and checks them through actual integration.
Which formula should you use to find the area: Look up "areas in polar coordinates," as I did. The formula is as follows:
Enclosed area = Integral from alpha to beta of (1/2)r^2 d(theta). Note that the initial radius here is 6 (since r = 4 plus 2 cos theta is 4+2 when theta = 0).