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postnew [5]
3 years ago
14

Company A can produce 100 CPUs in 3 days while Company B can produce 150 CPUs in 4 days. If the two companies join forces, how m

any days would it take them to produce 1000 CPUs?
Mathematics
2 answers:
jekas [21]3 years ago
8 0

Answer: They would need 15 days

Step-by-step explanation:

The data is:

Company A produce 100 CPUs in 3 days, so the rate per day is:

Ra = 100/3 CPUs per day: 33.33 CPUs per day.

Company B produce 150 CPUs in 4 days, then it produces:

Rb = 150/4 = 37.5 CPUs per day.

Then, if both companies work toggeter, they produce

Ra + Rb = 33.33 + 37.5 CPUs per day =  70.83 CPUs per day.

We want to know the number X of days needed to make 1000 CPUs, then we need to solve:

70.83*X = 1000

X = 1000/70.83 = 14.11 days, we could round it up to 15 days if we want to have a whole number.

OLga [1]3 years ago
8 0
I'm guessing it's about 16 days.

Hope this helped!
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Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet:
Phoenix [80]

6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

<u>Step-by-step explanation:</u>

We have , Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet: 1.25 cups of dry food. Based on these averages . We need to find  how many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks . We need to find how much they eat for 14 days as:

Trenton's pet: 4/5 cup of dry food•

With 4/5 per day , for 14 days :

⇒ 14(\frac{4}{5} )

⇒ 14(0.8 )

⇒ 11.2

Maria's pet: 1.25 cups of dry food.

With 1.25 per day , for 14 days :

⇒ 14(1.25 )

⇒ 17.5

Subtracting Maria's - Trenton's :

⇒ 17.5-11.2=6.3

That means , 6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

3 0
3 years ago
The perimeter of an isosceles trapezoid is 28 in and the ratio of lengths of its bases is 5:3. Find the lengths of the sides of
Natalka [10]
The measurements are:
b₁ = 8.4 inches; b₂ = 14 inches; leg₁ = 2.8 inches; leg₂ = 2.8 inches

Let x = length of base and leg

The formula for perimeter of isosceles trapezoid is P = b₁ + b₂ + 2(leg)
Where: b = base

       P = b₁ + b₂ + 2(leg)
     28 = 3x + 5x + 2(x)
     28 = 8x + 2x
28/10 = 10x/10
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Now, substitute the values:
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     28 = 3(2.8) + 5(2.8) + 2(2.8)
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     28 = 28

Hence the measurements are:
b₁ = 8.4 inches; b₂ = 14 inches; leg₁ = 2.8 inches; leg₂ = 2.8 inches
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On its first visit to the vet, Emma’s kitten weighed 30 ounces. On its second visit, the kitten had gained 8 ounces. On its thir
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Answer:

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