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postnew [5]
3 years ago
14

Company A can produce 100 CPUs in 3 days while Company B can produce 150 CPUs in 4 days. If the two companies join forces, how m

any days would it take them to produce 1000 CPUs?
Mathematics
2 answers:
jekas [21]3 years ago
8 0

Answer: They would need 15 days

Step-by-step explanation:

The data is:

Company A produce 100 CPUs in 3 days, so the rate per day is:

Ra = 100/3 CPUs per day: 33.33 CPUs per day.

Company B produce 150 CPUs in 4 days, then it produces:

Rb = 150/4 = 37.5 CPUs per day.

Then, if both companies work toggeter, they produce

Ra + Rb = 33.33 + 37.5 CPUs per day =  70.83 CPUs per day.

We want to know the number X of days needed to make 1000 CPUs, then we need to solve:

70.83*X = 1000

X = 1000/70.83 = 14.11 days, we could round it up to 15 days if we want to have a whole number.

OLga [1]3 years ago
8 0
I'm guessing it's about 16 days.

Hope this helped!
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A sequence is generated by the formula ax = 3x + 4. What is the value of the seventh term?
lyudmila [28]

Answer:

25

Explanation:

We are given the sequence formula expression;

ax = 3x + 4

You are to get the 7th term. This is gotten by substituting x = 7 into the expression as shown;

a7 = 3(7) + 4

a7 = 21 + 4

a7 = 25

Hence the seventh term of the sequence is 25

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1 year ago
the difference between a number and two times a number is seven the number is greater than zero what is the number
bagirrra123 [75]
7 is the answer

2x - x = 7
x = 7

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3 years ago
What is the quotation -3/8 divided by -1/4
Bumek [7]

Answer:

3/2

Step-by-step explanation:

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Answer:

6.85 oz

Step-by-step explanation:

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Linda can bicycle 48 miles in the same time as it takes her to walk 12 miles. She can ride 9 mph faster than she can walk. How f
Marrrta [24]

Answer:

\frac{48}{r+9}=\frac{12}{r}

Step-by-step explanation:

Let r represent Linda's walking rate.                      

We have been given that Linda can ride 9 mph faster than she can walk, so Linda's bike riding rate would be t+9 miles per hour.

\text{Time}=\frac{\text{Distance}}{\text{Rate}}

We have been given that Linda can bicycle 48 miles in the same time as it takes her to walk 12 miles.

\text{Time while riding}=\frac{48}{r+9}

\text{Time taken while walking}=\frac{12}{r}

Since both times are equal, so we will get:

\frac{48}{r+9}=\frac{12}{r}

Therefore, the equation \frac{48}{r+9}=\frac{12}{r} can be used to solve the rates for given problem.

Cross multiply:

48r=12r+108

48r-12r=12r-12r+108

36r=108

\frac{36r}{36}=\frac{108}{36}

r=3

Therefore, Linda's walking at a rate of 3 miles per hour.

Linda's bike riding rate would be t+9\Rightarrow 3+9=12 miles per hour.

Therefore, Linda's riding the bike at a rate of 12 miles per hour.

7 0
3 years ago
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