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Lera25 [3.4K]
3 years ago
13

If x/2+x=3, then x is what =

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
4 0
If you would like to solve the equation x/2 + x = 3 for x, you can do this using the following steps:

<span>x/2 + x = 3     /*2
</span>x + 2x = 3 * 2
3x = 6
x = 6/3
x = 2

The correct result would be x = 2.
lesya692 [45]3 years ago
3 0
X=2. If you add 2+2/2 it equals 3.
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55.76

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Which statement compares the two numbers correctly?
slamgirl [31]

Answer:

Step-by-step explanation:

So, we have-

(6 x .1) + (3 x .01) + (2  x .001)

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3 years ago
Do only equations with variables on both sides have no​ solution? Or can the variable be just on one​ side? Justify your answer.
Elis [28]

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4 0
3 years ago
3
Marianna [84]

The expression into a single logarithm is log[(x)^{10}][(2)^{30}]

Step-by-step explanation:

Let us revise some logarithmic rules

  • log(a)^{n}=nlog(a)
  • log(ab)=log(a)+log(b)
  • nlog(a)+mlog(b)=log[(a)^{n}][(b)^{m}]

∵ 10 log(x) + 5 log(64)

- At first re-write 10 log(x)

∴  10 log(x) = log(x)^{10}

- Then re-write 5 log(64)

∴  5 log(64) = log(64)^{5}

∴ 10 log(x) + 5 log(64) = log(x)^{10} + log(64)^{5}

- Use the 3rd rule above to make it single logarithm

∵ log(x)^{10} + log(64)^{5} = log[(x)^{10}][(64)^{5}]

∴ 10 log(x) + 5 log(64) = log[(x)^{10}][(64)^{5}]

∵ 64 = 2 × 2 × 2 × 2 × 2 × 2

∴ We can write 64 as 2^{6}

∴ (64)^{5}=(2^{6})^{5}

- Multiply the two powers of 2

∴ (64)^{5}=(2)^{30}

∴ 10 log(x) + 5 log(64) = log[(x)^{10}][(2)^{30}]

The expression into a single logarithm is log[(x)^{10}][(2)^{30}]

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

6 0
3 years ago
Detroit Windsor tunnel is an underwater highway that connects the cities in Detroit Michigan in Windsor Ontario. How many times
Bond [772]

Answer:

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Step-by-step explanation:

The complete question in the attached figure

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