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Mathematics

1 answer:

AVprozaik [17]4 years ago

7 0

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In 1987, the population of country A was estimated at 87 million people, with an annual growth rate of 3.5%. The 1987 population

KATRIN_1 [288]

Answer:

Step-by-step explanation:

Given that in 1987, the population of country A was estimated at 87 million people, with an annual growth rate of 3.5%

Thus the equation for population for country A would be

$P(A) = 87e^{0.035t}$

The 1987 population of country B was estimated at 243 million with an annual growth rate of 0.6%.

So equation for population for country B would be

$P(B) = 243e^{0.006t}$ where t = time in years and P in millions

a) P(A) = 2*87 when

$2=e^{0.035t}$

Take log and solve

ln 2 = 0.005 t

t = 138.63

Thus after 138 years population will double for A

b) P(A) = P(B) when

$P(A) = 87e^{0.035t}=P(B) = 243e^{0.006t}\\e^{0.035t-0.006t}=\frac{243}{87} =2.793\\0.029t = 1.027\\t= 35.42$

Approximately after 35.5 years the populations of both countries would be equal.

7 0

3 years ago

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Solve x2 – 4x – 9 = 29 for x.

Irina-Kira [14]

$x^2 - 4x - 9 = 29 \\ x^2 - 4x - 9 - 29 = 0 \\ x^2 - 4x - 38 = 0 \\ x= \frac{-b \pm \sqrt{ b^{2} -4ac} }{2a} 
$ ; where a = 1, b = -4 and c = -38
$x= \frac{-(-4) \pm 
\sqrt{ 
(-4)^{2} -4 \times 1 \times -38} }{2 \times 1} \\ = \frac{4 \pm \sqrt{ 16 +152} }{2} \\ =\frac{4 \pm \sqrt{ 168} }{2} \\ =\frac{4 \pm 
2\sqrt{42} }{2} \\ 
=2+\sqrt{42} \ or \ 2-\sqrt{42}\\=8.48 \ or \ -4.48$

8 0

3 years ago

Read 2 more answers

Lets see who is smart lol

Simora [160]

9514 1404 393

Answer:

$\square\quad{y=\dfrac{1}{2}x+4}\\\\\square\quad{\dfrac{y-5}{x-2}=\dfrac{1}{2}}$