I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).
Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system
- y + 3z = -2
y + z = -2
-----------------
4z = -4, so z = -1.
Next, multiply the 3rd equation by 2: You'll get -2x + 2y + 2z = -2.
Add this result to the first equation. The 2x terms will cancel, leaving you with the system
2y + 2z = -2
y + z = 4
This would be a good time to subst. -1 for z. We then get:
-2y - 2 = -2. Then y must be 0. y = 0.
Now subst. -1 for z and 0 for y in any of the original equations.
For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.
Then a tentative solution is (-3, -1, 0).
It's very important that you ensure that this satisfies all 3 of the originale quations.
The circumference = π x the diameter of the circle (Pi multiplied by the diameter of the circle). Simply divide the circumference by π and you will have the length of the diameter. The diameter is just the radius times two, so divide the diameter by two and you will have the radius of the circle
First, change the two mixed numbers in the expression into an improper fraction: 25/6 + 5/3.
Then, find the Lowest Common Denominator of both fractions, which is 6, and set both denominators equal to that. Remember, whatever you do on one side you must do to the other: 25/6 + 10/6
Add the two together: 25/6 +10/6 = 35/6.
To make it a mixed number again, find how many times 6 goes into 35, which is 5 times, with a remainder of 5. Your answer is 5 5/6
Answer:
Step-by-step explanation:
Given: 
Initial value: y(1)=6
Let 
Variable separable
Integrate both sides
Initial condition, y(1)=6
Put C into equation
Solution:
or
Hence, The solution is or
