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galben [10]
3 years ago
8

Simplify: (-4+√3)^2 19 – 8√3 –5 –4√3 19+8√3 16 + 8√3

Mathematics
1 answer:
N76 [4]3 years ago
5 0
It is a because when squared the product ensues as such so A Is the value
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Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
zheka24 [161]
<h2>Hello!</h2>

The answer is:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance which is equal to 264 miles of distance in 2 hours + 45 minutes, we  have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation, we have:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

We have that the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

Hence, we have that:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

4 0
3 years ago
Read 2 more answers
Rationalize the denominator of \frac{1 \sqrt{3}}{1-\sqrt{3}}. When you write your answer in the form A B\sqrt{C}, where A, B, an
kobusy [5.1K]

Answer:

The value of ABC is 6.

Step-by-step explanation:

Consider the expression

\frac{1+\sqrt{3}}{1-\sqrt{3}}

Rationalize the denominator.

\frac{1+\sqrt{3}}{1-\sqrt{3}}\times \frac{1+\sqrt{3}}{1+\sqrt{3}}

\frac{(1+\sqrt{3})^2}{1^2-(\sqrt{3})^2}

\frac{1^2+(\sqrt{3})^2+2\sqrt{3}}{1-3}

\frac{1+3+2\sqrt{3}}{-2}

\frac{4+2\sqrt{3}}{-2}

\frac{4}{-2}+\frac{2\sqrt{3}}{-2}

-2-\sqrt{3}              ..... (1)

The answer in the form

A+B\sqrt{C}           .... (2)

On comparing (1) and (2), we get

A=-2,B=-1,C=3

We need to find the value of ABC.

ABC=(-2)(-1)(3)=6

Therefore the value of ABC is 6.

7 0
3 years ago
What number, when subtracted by 15, equals 18?
ad-work [718]

Answer:

23

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is ( 3/10 being a fraction ) 5 3/10 - 7.8
Tpy6a [65]
5.3 -7.8 =

-2.5 or

-2  1/2
6 0
3 years ago
Read 2 more answers
Use the information to find and compare Δy and dy. (Round your answers to three decimal places. )
Alisiya [41]

The computation shows that the values of Δy and dy will be 0.572 and 0.4 respectively.

<h3>How to compute the values?</h3>

The value of Δy will be computed thus:

Δy = y(x + Δx) - y(x)

= y(1.1) - y(1)

= 0.5(1.1)⁸ - 0.5(1)⁸

= 0.572

The value of dy will be:

= y'(x)dx

= (0.5)⁸ × x⁷(0.1)

= 0.4 (1)⁷

= 0.4

Learn more about finding values on:

brainly.com/question/25927269

7 0
2 years ago
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