<h3>
Answer: 7/10</h3>
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Explanation:
There are 30 days in April. Since it rained 9 of those days, the empirical probability of it raining in April is 9/30 = (3*3)/(3*10) = 3/10.
If we assume that the same conditions (ie weather patterns) hold for May, then the empirical probability of it raining in May is also 3/10. By "raining in May", I mean specifically raining on a certain day of that month.
The empirical probability of it not raining on the first of May is therefore...
1 - (probability it rains)
1 - (3/10)
(10/10) - (3/10)
(10-3)/10
7/10
We can think of it like if we had a 10 day period, and 3 of those days it rains while the remaining 7 it does not rain.
The answer is 103 it's false
Answer:
f(2) =5
Step-by-step explanation:
We have a function f(x) = 3x-1
When we find f(2) ,let x=2
f(2) = 3*2-1
= 6-1
=5
Find A first by using formula: (a+b)/2= midpoint
so: A = [(-17)+(55)]/2
= 36
Now find B using midpoint formula:
B: (a+b)/2
=36+0/2
=18
