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zhenek [66]
3 years ago
9

if los angeles county wants to know what percent of its citizens have children who are in school readiness support, which method

will be best to gather the information and why
Mathematics
1 answer:
Montano1993 [528]3 years ago
7 0
Going downtown Because you can easily count
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32, 28, 21, 31, 18<br><br> Is 18 an outlier or no?
Kryger [21]

Answer:

No because 21 is close to it.

Step-by-step explanation:

To be considered an outlier, it would need to be a farther distance such as the distance from 28 to 21.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

4 0
4 years ago
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Evaluate the expression.<br> (-5)(5) +5=
Ierofanga [76]

Answer:

Step-by-step explanation:

Here you go mate

Step 1

(-5)(5) +5  Equation

Step 2

(-5)(5) +5 Simplify

(-5)(5) +5

Step 3

(-5)(5) +5  Add and multiply them

(-25)+5

answer

-20

8 0
3 years ago
Solve the inequality.
mr Goodwill [35]

Answer:

the first one, v < 1 23/25

Step-by-step explanation:

multiply both sides by 6 and divide by 5

v < 48/25, or v < 1 23/25

5 0
3 years ago
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What fraction of 5 is 1/2​
Sphinxa [80]

Answer:

1/10

Step-by-step explanation:

1/2 divided by 5 = 1/10

7 0
3 years ago
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The area of the shaded segment is 100cm^2. Calculate the value of r.
Reil [10]
Hello, 

The formula for finding the area of a circular region is: A=  \frac{ \alpha *r^{2} }{2}

then:
A_{1} = \frac{80*r^{2} }{2}

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

cos(40)= \frac{h}{r}  \\  \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)

Now we can find its area:
A_{2}=2* \frac{b*h}{2}  \\  \\ A_{2}= [r*sen(40)][r*cos(40)]\\  \\A_{2}= r^{2}*sen(40)*cos(40)

The subtraction of the two areas is 100cm^2, then:

A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm

Answer: r= 1.59cm
7 0
3 years ago
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