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Marina86 [1]
3 years ago
13

3x²-6x i need the answer for this question

Mathematics
1 answer:
weeeeeb [17]3 years ago
7 0
<span><span>3<span>x^2</span></span>−<span>6x</span></span><span>  =<span><span>3x</span><span>(<span>x−2</span>)</span></span></span>  Answer:<span><span>3x</span><span>(<span>x−2</span><span>)</span></span></span>
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Answer:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
What is the solution of the system? Use elimination.
sweet [91]

Answer:

The solutions to the system of the equations by the elimination method will be:

x=2,\:z=-1,\:y=2

Step-by-step explanation:

Given the system of the equations

2x\:+\:2y\:+z\:=\:7

-x-\:y\:+z\:=\:-5

x+3y-4z=12

solving the system of the equations by the elimination method

\begin{bmatrix}2x+2y+z=7\\ -x-y+z=-5\\ x+3y-4z=12\end{bmatrix}

\mathrm{Multiply\:}-x-y+z=-5\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:-2x-2y+2z=-10

\begin{bmatrix}2x+2y+z=7\\ -2x-2y+2z=-10\\ x+3y-4z=12\end{bmatrix}

-2x-2y+2z=-10

+

\underline{2x+2y+z=7}

3z=-3

\begin{bmatrix}2x+2y+z=7\\ 3z=-3\\ x+3y-4z=12\end{bmatrix}

2x+6y-8z=24

-

\underline{2x+2y+z=7}

4y-9z=17

\begin{bmatrix}2x+2y+z=7\\ 3z=-3\\ 4y-9z=17\end{bmatrix}

Rearranging the equations

\begin{bmatrix}2x+2y+z=7\\ 4y-9z=17\\ 3z=-3\end{bmatrix}

solve 3z=-3 for z:

z=-1

\mathrm{For\:}4y-9z=17\mathrm{\:plug\:in\:}z=-1

solve  4y-9\left(-1\right)=17 for y:

4y-9\left(-1\right)=17

4y+9=17

4y=8

y=2

\mathrm{For\:}2x+2y+z=7\mathrm{\:plug\:in\:}z=-1,\:y=2

solve 2x+2\cdot \:2-1=7 for x:

2x+2\cdot \:2-1=7

2x+3=7

2x=4

x=2

Therefore, the solutions to the system of the equations by the elimination method will be:

x=2,\:z=-1,\:y=2

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One hundred divided by twice a number is ten
Ludmilka [50]

\frac{100}{2x} = 10

Are you trying to find x, or are you only suppose to translate it?

If you are trying to find x, you first multiply 2x on both sides

100 = 10(2x)

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Divide 2 on both sides

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3 years ago
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