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xz_007 [3.2K]
3 years ago
5

Please help and explain

Mathematics
1 answer:
Anastasy [175]3 years ago
6 0

Answer: The probability for both is 1/2

Step-by-step explanation:

For A. The probability for who do or do not participate in some kind of sport is found by adding the students who do or do not. Which is 25 + 225 = 250

250 out of 500 simplified is 1/2

For B. The probability got who do and do not participate in some kind of sport is found by taking the number of students out of the whole number. Its 250 out of 500.

250 out of 500 is simplified to 1/2.

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A brand new video game system sells for $340. If the sales tax is 6.98%, how much will the new video game
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$363.73
The sales tax is $23.73

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6 0
3 years ago
A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?
seraphim [82]

Answer:

P\left(E\right)=\frac{55}{1024}

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

nCr=\frac{n!}{r!\left(n-r\right)!}

Plug in n = 12 and r = 9

       =\frac{12!}{9!\left(12-9\right)!}

       =\frac{12!}{9!\cdot \:3!}

       =\frac{12\cdot \:11\cdot \:10}{3!}            ∵ \frac{12!}{9!}=12\cdot \:11\cdot \:10

       =\frac{1320}{6}                   ∵ 3!\:=\:3\times 2\times 1=6

       =220

Thus, the probability will be:

P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}

         =\frac{220}{4096}

         =\frac{55}{1024}

Thus, the probability of the coin landing tails up exactly nine times will be:

P\left(E\right)=\frac{55}{1024}

4 0
3 years ago
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