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2 years ago

Solve the system of equations y=2x-3 and y=x^2-3

Mathematics

2 answers:

KatRina [158]2 years ago

7 0

I have attached some answers in the photos below hope you find them useful

beks73 [17]2 years ago

6 0

Answer:

0 and 1

Step-by-step explanation:

Given :

$y= 2x-3\\y=2x^{2} -3$

Now equate the both equation :

$2x-3=2x^{2} -3$

2x=2 $x^{2}$

x- $x^{2}$ =0

x(1-x)=0

x=0

1-x=0

x=1

Therefore, x=0,1

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