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never [62]
2 years ago
7

Solve the system of equations y=2x-3 and y=x^2-3

Mathematics
2 answers:
KatRina [158]2 years ago
7 0

I have attached some answers in the photos below hope you find them useful

beks73 [17]2 years ago
6 0

Answer:

0 and 1

Step-by-step explanation:

Given :

y= 2x-3\\y=2x^{2} -3

Now equate the both equation :

2x-3=2x^{2} -3

2x=2x^{2}

x-x^{2}=0

x(1-x)=0

x=0

1-x=0

x=1

Therefore, x=0,1

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