Answer:
0.7432m²
1152in²
Explanation:
a) Usng the conversion
1ft² = 0.0929m²
8ft² = y
y = 8 × 0.0929
y = 0.7432m²
Hence 8ft² in m² is 0.7432m²
For ft² to in²
1ft² = 144in²
8ft² = x
X =8×144
x = 1152in²
Hence 8ft² expressed in in² is 1152in²
The Correct Answer is <u>D.Infrared/</u> <em>INFARED has a lower frequency than visible light/</em>
Answer:
a)v = 476.28 m / s
, b) T = 6.69 10⁵ N
, c) λ = 0.486 m
, d) λ = 0.35 m
Explanation:
a) The speed of a wave on a string is
v = √T /μ
also all the waves fulfill the relationship
v = λ f
they indicate that the fundamental frequency is f = 980 Hz.
The wavelength that is fixed at its ends and has a maximum in the center
L = λ / 2
λ = 2L
we substitute
v = 2 L f
let's calculate
v = 2 0.243 980
v = 476.28 m / s
b) The tension of the rope
T = v² μ
the density of the string is
μ = m / L
T = v² m / L
T = 476.28² 0.717 / 0.243
T = 6.69 10⁵ N
c) λ = 2L
λ = 2 0.243
λ = 0.486 m
d) The violin has a resonance process with the air therefore the frequency of the wave in the air is the same as the wave in the string. Let's find the wavelength in the air
v = λ f
λ= v / f
λ = 343/980
λ = 0.35 m
Answer:
980 J, B
Explanation:
Given that.
mass of substance, m = 75 g
initial temperature of system, θ1 = 150° C
final temperature of system, θ2 = 250° C
specific heat capacity, c = 0.13 J/gC
Q = mcΔθ, where
Q = quantity of heat required in J
m = mass of substance in G
c = specific heat capacity of substance in J/gC
Δθ = change in temperature °C
Δθ = θ2 - θ1
Δθ = 250° C - 150° C
Δθ = 100° C
now that we have all our values, what we do next is to substitute and apply all in the initial formula given
Q = mcΔθ
Q = 75 * 0.13 * 100
Q = 7500 * 0.13
Q = 975 J
Thus, we can say they amount of heat required to increase the temperature of 75g of gold, from 150° - 250° is 975 J, which is approximately, 980 J.
Option B
Answer:
5.76 cm³
Explanation:
Using the equation for volume expansivity,
V = V₀ + V₀γΔθ) where V₀ = volume of cube = volume of mercury = 400 cm³, γ = cubic expansivity of mercury = 18 × 10⁻⁵ /K and Δθ temperature change = θ₂ - θ₁ where θ₁ = 0 °C and θ₂ = 80°C. So, Δθ = 80°C - 0°C = 80°C = 80 K
Now, the volume change, ΔV = V - V₀ = V₀γΔθ.
So, substituting the values of the variables into the equation, we have
ΔV = V₀γΔθ
= 400 cm³ × 18 × 10⁻⁵ /K × 80 K
= 5.76 cm³
So the mercury will overflow by 5.76 cm³.