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3 years ago

10

You have learned how to create an effective study space in this learning path.

1 answer:

Rudiy273 years ago

5 0

Answer:

Getting comfy but not too comfy

Explaination : Some people work the majority of their lives in sweat pants and a grungy t-shirt; others dress in full business attire before sitting down at the desk in their study. Because I want to enjoy the place where I study, I say be comfortable—but not too comfortable. I change out of my pajamas before I crack open my books to give my mind another signal that this isn’t lounge time, but study time.

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Define Bernoulli's principle

Serhud [2]

It's when an increase in a liquid's speed creates an el pressure decrease in a liquid'ss speed and creates a pressure increase. <3

6 0

3 years ago

Read 2 more answers

A 3.00 m-long 6.00-kg ladder pivoted at the top hangs down from a platform at the circus. A 42.0-kg trapeze artist climbs to a p

statuscvo [17]

Answer:

The period of the system of ladder and woman, T = 2.5 seconds

Explanation:

Mass of the ladder, $m_1 = 6 kg$

Mass of the artiste, $m_2 = 42.0 kg$

Length of the ladder, L = 42.0 kg

The total moment of inertia can be calculated using the equation:

$I = \frac{1}{3} M_1 L^2 + m_2 (\frac{L}{2} )^2\\I = \frac{1}{3} *6*3^2 + 42* (\frac{3}{2} )^2\\I = 18 + 94.5\\I = 112.5 kg m^2$

D = L/2 = 3/2

D = 1.5 m

The frequency of the system of ladder and woman follows that of a physical pendulum which can be given by the equation:

$f = \frac{1}{2\pi } \sqrt{\frac{mgD}{I} } \\f = \frac{1}{2\pi } \sqrt{\frac{48*9.8*1.5}{112.5} }\\f = 0.4$

The period of the system of ladder and woman is given by:

T = 1/f

T = 1/0.4

T = 2.5 seconds

5 0

3 years ago

A 91.1 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.73 r

KIM [24]

Answer:

$\omega_f = 1.08 rad/s$

Explanation:

As we know that there is no external torque on the system of platform, banana and the monkey

so the angular momentum of the system will remains conserved

so here we can say

$L_i = L_f$

$I_o\omega = (I_o + m_1r_1^2 + m_2r_2^2)\omega_f$

here we know that

$I_o = \frac{1}{2}mR^2$

$I_o = \frac{1}{2}(91.1)(1.61)^2 = 118.1 kg m^2$

$m_1 = 9.41 kg$

$r_1 = \frac{4}{5}(1.61) = 1.29 m$

$m_2 = 21.1 kg$

Now from above equation

$118.1(1.73) = (118.1 + 9.41(1.29^2) + 21.1(1.61^2))\omega_f$

$118.1(1.73) = 188.45\omega_f$

$\omega_f = 1.08 rad/s$

8 0

3 years ago

It is determined that a certain light wave has a wavelength of 3.012 x 10-12 m. The light travels at 2.99 x 108 m/s. What is the

gayaneshka [121]

Answer:

id.k

Explanation:

3 0

3 years ago

1. Two astronauts are 2.00 m apart in their spaceship. One speaks to the other. The conversation is transmitted to earth via ele

Veronika [31]

Answer:

$1.6949*10^6 m$

Explanation:

Our values are

$d=2m$

$v=354m/s$

We can find the time through

$t=\frac{d}{v}$

$t=\frac{2}{354}$

$t=5.64*10^{-3}s$

The expression for the distance between the Earth and the spaceship is as follow:

$d=ct$

Where c is Light speed, and t our previous time.

$d= (3*10^8)(5.64*10^{-3})$

$d= 1.6949*10^6m$

Therefore the distance between the Eath and the Spaceship is $1.6949*10^6$ m

4 0

4 years ago