All categories

2 years ago

Which part of the electromagnetic spectrum has a lower frequency than visible light?

Physics

2 answers:

Mademuasel [1]2 years ago

6 0

The Correct Answer is D.Infrared/ INFARED has a lower frequency than visible light/

KonstantinChe [14]2 years ago

4 0

Ultraviolet part of the electromagnetic spectrum has higher frequency than the visible light.

X-ray part of the electromagnetic spectrum has higher frequency than the visible light.

gamma rays part of the electromagnetic spectrum has higher frequency than the visible light.

infrared red part of the electromagnetic spectrum has lower frequency than the visible light.

hence the correct choice is infrared

You might be interested in

In 1949, an automobile manufacturing company introduced a sports car (the "Model A") which could accelerate from 0 to speed v in

Fudgin [204]

Answer: $\frac{P_B}{P_A}$ = 8.5264

Explanation: Power is the rate of energy transferred per unit of time: P = $\frac{E}{t}$

The energy from the engine is converted into kinetic energy, which is calculated as: $KE = \frac{1}{2}.m.v^{2}$

To compare the power of the two cars, first find the Kinetic Energy each one has:

K.E. for Model A

$KE_A = \frac{1}{2}.m.v^{2}$

K.E. for model B

$KE_B = \frac{1}{2}.m.(2.92v)^{2}$

$KE_B = \frac{1}{2}.m.8.5264v^{2}$

Now, determine Power for each model:

Power for model A

$P_{A}$ = $\frac{m.v^{2} }{2.t}$

Power for model B

$P_B = \frac{m.8.5264.v^{2} }{2.t}$

Comparing power of model B to power of model A:

$\frac{P_B}{P_A} = \frac{m.8.5264.v^{2} }{2.t}.\frac{2.t}{m.v^{2} }$

$\frac{P_B}{P_A} =$ 8.5264

Comparing power for each model, power for model B is 8.5264 better than model A.

7 0

3 years ago

Create a group of 3-4 students. Using your cell phone flashlight and the filter, create a "blue" flashlight, "red" flashlight, a

Korvikt [17]

Answer:

the light creates sorta a mixture of all the colors on the white index card.

4 0

2 years ago

2 Points

liberstina [14]

A- electrical energy to kinetic energy

8 0

2 years ago

Read 2 more answers

A young woman was found dead on the side of the road. Two witnesses said they saw and red cadillac hit her and drive off earlier

nignag [31]

I think the answer would be A. Density because many headlights could have the same density, but the rest of the analysis techniques would be specific to that crime.

7 0

3 years ago

(d) If η = 40% and TH = 427°C, what is TC, in °C?

Brrunno [24]

Answer:

$T_C=256.2^{\circ}C$

Explanation:

Given that,

Efficiency of heat engine, $\eta=40\%=0.4$

Temperature of hot source, $T_H=427^{\circ}C$

We need to find the temperature of cold sink i.e. $T_C$ . The efficiency of heat engine is given by :

$\eta=1-\dfrac{T_C}{T_H}$

$T_C=(1-\eta)T_H$

$T_C=(1-0.4)\times 427$

$T_C=256.2^{\circ}C$

So, the temperature of the cold sink is 256.2°C. Hence, this is the required solution.

3 0

3 years ago