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Masteriza [31]
3 years ago
10

A crate weighing 1000 Newton's needs to be lifted at a constant speed from the ground to a loading dock 1.5 meters high in 5.0 s

econds. What power is required to lift the crate?
Physics
1 answer:
miskamm [114]3 years ago
3 0

Answer:

the Power required is 300 W

Explanation:

We know that the definition of work is given by the following expresion:

W=F*d

the distance is 1.5 meters and the Force is equal to 1000 N.

Replacing this values in the work expresion

w= 1000 *1.5 = 1500 J

And the power is equal to the amount of work done in a given time, therefore we have:

Power = \frac{work}{time} \\

Time in seconds

Power = 1500/5\\\\Power = 300 watts

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nataly862011 [7]

Answer:

When something is transparent, it means that it allows light to pass through or is see-through . For example:

1) glass

2) air

3) some plastics

7 0
3 years ago
Read 2 more answers
sledge (including load) weighs 5000 N. It is pulled on level snow by a dog team exerting ahorizontal force on it. The coefficient
lara31 [8.8K]

Answer:

2.5 x 10^{5} J

Explanation:

weight = 5,000 N

coefficient of friction = 0.05

distance = 1000 m

how much work is done by the dogs pulling the sledge

work done = force x coefficient of friction x distance

work done = 5000 x 0.05 x 1000 = 2.5 x 10^{5} J

6 0
4 years ago
Why are you able to observe the Doppler effect on earth with sound waves but not with light waves?
VladimirAG [237]

Answer: When an ambulance passes with its siren blaring, you hear the pitch of the siren change: as it approaches, the siren’s pitch sounds higher than when it is moving away from you. This change is a common physical demonstration of the Doppler effect.

Explanation:

6 0
4 years ago
A certain parallel-plate capacitor is filled with a dielectric for which Κ = 5.5 .The area of each plate is 0.034 m2 , and the p
Nesterboy [21]

Answer:

The maximum energy that can be stored in the capacitor is  6.62 x 10⁻⁵ J

Explanation:

Given that,

dielectric constant k = 5.5

the area of each plate, A = 0.034 m²

separating distance, d =  2.0 mm = 2 x 10⁻³ m

magnitude of the electric field =  200 kN/C

Capacitance of the capacitor is calculated as follows;

C = \frac{k \epsilon A}{d} = \frac{5.5*8.85*10^{-12}*0.034}{2*10^{-3}} = 8.275 *10^{-10} \ F

Maximum potential difference:

V = E x d

V = 200000 x 2 x 10⁻³ = 400 V

Maximum energy that can be stored in the capacitor:

E = ¹/₂CV²

E = ¹/₂ x 8.275 x 10⁻¹⁰ x (400)²

E = 6.62 x 10⁻⁵ J

Therefore, the maximum energy that can be stored in the capacitor is  6.62 x 10⁻⁵ J

4 0
3 years ago
A small block with a mass of 0.120 kg is attached to a cord passing through a hole in a frictionless, horizontal surface (Fig. 6
Rina8888 [55]

Answer:

a) 0.147 N

b) 9.408 N

c) 9.261 N

Explanation:

The tension on the cord is the only force keeping the block in circular motion, thus representing the entirety of its centripetal force \frac{mv^{2} }{r}. Plugging in values for initial and final states and we get answers for a and b. The work done by the person causes the centripetal force to increase, and thus is the difference between the final tension and the initial tension.

7 0
3 years ago
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