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Wittaler [7]
3 years ago
12

In an electron dot diagram, the symbol for an element is used to represent

Physics
2 answers:
SIZIF [17.4K]3 years ago
7 0
A the nucleus bruh it can't be anything else
Ede4ka [16]3 years ago
4 0

Answer : The correct option is, (A) the nucleus.

Explanation:

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The representation of valence electrons of an atom by dots around the symbol of an element is said to be the electron dot symbol.

In an electron dot diagram, the symbol for an element is used to represent the nucleus.

For example :

As we know that arsenic has '5' valence electrons. So, the symbol (As) is used to represent the nucleus and valance electrons around the is represented by the 'dot'.

The Lewis-dot structure of As (arsenic) is shown below.

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It continues to fly along the same horizontal arc but increases its speed at the rate of 1.34 m/s 2 . Find the magnitude of acce
shepuryov [24]

This Question is not complete

Complete Question:

a. A hawk flies in a horizontal arc of radius 11.3 m at a constant speed of 5.7 m/s. Find its centripetal acceleration.

Answer in units of m/s2

b. It continues to fly along the same horizontal arc but increases its speed at the rate of 1.34 m/s2. Find the magnitude of acceleration under

these new conditions.

Answer in units of m/s2

Answer:

a. 2.875m/s²

b. 3.172m/s²

Explanation:

a. The formula for centripetal acceleration = (speed²) ÷ radius

Centripetal acceleration = (5.7m/s)²÷ 11.3m

Centripetal acceleration = 2.875m/s²

b. Magnitude of acceleration can be calculated by finding the sum of the vectors for the both the centripetal acceleration and the increase in the speed rate.

Centripetal acceleration ( acceleration x) = 2.875m/s²

Increase in the speed rate ( acceleration n) = 1.34m/s²

Magnitude of acceleration = √a²ₓ + a²ₙ

=√( 2.875m/s²)²+ (1.34m/s²)²

= √ 10.06m/s²

= 3.172m/s²

3 0
4 years ago
Read 2 more answers
3. A model rocket is launched straight upward at 58.8 m/s.
SIZIF [17.4K]

Let us assume that rocket only runs in initial energy and not using its own to flying.

Also , let upward direction is +ve and downward direction is -ve .

Initial velocity , u = 58.8 m/s .

Acceleration due to gravity , g=-9.8\ m/s^2 .

Final velocity , v - = 0 m/s .

We know , by equation of motion .

v^2-u^2=2gh\\\\2gh_{max}=0^2-58.8^2\\\\h_{max}=\dfrac{0^2-58.8^2}{-2\times 9.8}\\\\h_{max}= 176.4\ m

Hence, this is the required solution .

8 0
3 years ago
Reacting molecules must hit each other with sufficient energy in order to form products,what theory is it
7nadin3 [17]
It is called Arrhenius collision theory.
4 0
3 years ago
What tool is used to measure air pressure?
alukav5142 [94]
A<span> barometer is used to measure air pressure. </span>
8 0
4 years ago
An internal resistance of 5 ohm and a battery of 15 ohm is connected to a resistance of 20 ohm calculate the electric current
Allushta [10]

Answer:

.6 A

Explanation:

Battery 15 VOLTS

V = IR

V / R = I

15 / ( 5+20) = .6 amps

5 0
2 years ago
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