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yawa3891 [41]
3 years ago
6

The area of the trapezoid

Mathematics
2 answers:
never [62]3 years ago
8 0

Answer:

\boxed{\bold{82.5 \ In.^2}}

Step By Step Explanation:

Area Of Trapezoid: \bold{\frac{a+b}{2}Height }

[ Find 'a' & 'b' ]

a: 5 In.

b: 10 In.

Height: 11 In.

[ Insert Numbers Into Equation ]

\bold{\frac{5+10}{2} \ \cdot \ 11 }

[ Solve ]

5 + 10 = 15

15 ÷ 2 = 7.5

7.5 · 11 = 82.5

ELEN [110]3 years ago
7 0

Answer:

<h2>A = 82.5 in²</h2>

Step-by-step explanation:

The formula of an area of a trapezoid:

A=\dfrac{b_1+b_2}{2}\cdot h

b₁, b₂ - bases

h - height

We have b₁ = 10in, b₂ = 5in and h = 11in. Substitute:

A=\dfrac{10+5}{2}\cdot11=\dfrac{15}{2}\cdot11=7.5\cdot11=82.5\ in^2

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Levart [38]
The slope is -2/3.

You have to do -2-2 and you get -4.
Then you do 12-6 and you get 6.
The final step is to do -4 divide 6 and you get -2/3.
5 0
2 years ago
If angle EFH(5x+1)’ angle HFG(62 degrees) and angle EFG (18x+11) find each measurement
zloy xaker [14]

Answer:

∠EFH = 21°

∠HFG = 62°

∠EFG = 83°

Step-by-step explanation:

The diagram showing the angles has been attached to this response.

From the diagram, it can be deduced that;

Angle EFG = angle EFH + angle HFG

=> ∠EFG = ∠EFH + ∠HFG                -------------------(i)

From the question:

∠EFH = (5x + 1)°                    -------------(ii)

∠HFG = 62°                          -------------(iii)

∠EFG = (18x + 11)°                 -------------(iv)

<em>Substitute these values into equation (i) as follows;</em>

(18x + 11) = (5x + 1) + 62

=> 18x + 11 = 5x + 1 + 62

<em>Collect like terms and solve for x</em>

18x - 5x = 1 + 62 - 11

13x = 52

x = 4

Now, to get each measurement, substitute x = 4 into each of equations (ii) - (iv)

∠EFH = (5x + 1)°

∠EFH = (5(4) + 1)°

∠EFH = (20 + 1)°

∠EFH = 21°

∠HFG = 62°              [<em>Does not depend on x</em>]

∠EFG = (18x + 11)°

∠EFG = (18(4) + 11)°

∠EFG = (72 + 11)°

∠EFG = 83°

<u>Conclusion:</u>

∠EFH = 21°

∠HFG = 62°

∠EFG = 83°

8 0
3 years ago
In triangle CDE, CD= 12 , DE=5, and m<br> What is m
steposvetlana [31]
If you could show a photo I could answer the question
5 0
2 years ago
During the first seconds after takeoff, a rocket traveled 208 kilometers in 50 minutes at al
lukranit [14]

Answer:

The rocket has a faster unit rate and is 219\ km/h much faster than the penny

Step-by-step explanation:

Find the unit rate of each object and the compare the results

step 1

Find the unit rate per hour of the rocket

To find the unit rate divide the total distance by the time

Let

d -----> the distance in km

t -----> the time in hours

we have

d=208\ km

t=50/60=5/6\ h

Find the unit rate

208/(5/6)=208*6/5=249.6\ km/h

step 2

Find the unit rate per hour of the penny

To find the unit rate divide the total distance by the time

Let

d -----> the distance in km

t -----> the time in hours

we have

d=153\ km

t=5\ h

Find the unit rate

153/5=30.6\ km/h

step 3

Compare the unit rates

The units rate of rocket is 249.6\ km/h

The unit rate of penny is 30.6\ km/h

Find the difference

249.6-30.6=219\ km/h

therefore

The rocket has a faster unit rate and is 219\ km/h much faster than the penny

8 0
3 years ago
ADD: (8x3+ 3x2 + 4 ) + (12x5 - 7x3 + 6x2)
Shkiper50 [21]

The answer is: 12x5+x3+9x2+4

This is the correct answer because all of the exponents are in the correct calculation and the numbers as well.

I hoped this helped! :)

8 0
3 years ago
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