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2 years ago

WILL MARK BRAINLIEST!!!

Mathematics

1 answer:

koban [17]2 years ago

4 0

Answer:

150

Step-by-step explanation:

1800 ÷ 12 = 150

you get 1800 by doing 180(12 -2) b/c the equation is 180(x -2) gives you all the angles togther

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Please help work this equation

Flauer [41]

Hi!

<u>Given these two equations:</u>

$x = y + 8$

$x + 4 = 2(y + 4)$

We want to solve using the substitution method. Knowing that x is equal to y + 8, we can simply plug in 'y + 8' in for x in the second equation, like so:

$(y+8)+4=2(y+4)$

Combine like terms on both sides:

$y+12=2y+8$

Subtract y from both sides:

$12=y+8$

Subtract 8 from both sides:

$y=4$

Now, we can simply plug the y value in to the first equation, and solve for x:

$x=4+8$

Simplify:

$x=12$

<h3>Therefore, x is equal to 12 and y is equal to 4.</h3>

<u>Learn more about the substitution (and also elimination!) method here:</u>

brainly.com/question/14619835

4 0

2 years ago

Please dont ignore, Need help!!! Use the law of sines/cosines to find..

Ket [755]

Answer:

16. Angle C is approximately 13.0 degrees.

17. The length of segment BC is approximately 45.0.

18. Angle B is approximately 26.0 degrees.

15. The length of segment DF "e" is approximately 12.9.

Step-by-step explanation:

By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.

For triangle ABC:

$\sin{A} = \sin{103\textdegree{}}$ ,
The opposite side of angle A $a = BC = 26$ ,
The angle C is to be found, and
The length of the side opposite to angle C $c = AB = 6$ .

$\displaystyle \frac{\sin{C}}{\sin{A}} = \frac{c}{a}$ .

$\displaystyle \sin{C} = \frac{c}{a}\cdot \sin{A} = \frac{6}{26}\times \sin{103\textdegree}$ .

$\displaystyle C = \sin^{-1}{(\sin{C}}) = \sin^{-1}{\left(\frac{c}{a}\cdot \sin{A}\right)} = \sin^{-1}{\left(\frac{6}{26}\times \sin{103\textdegree}}\right)} = 13.0\textdegree{}$ .

Note that the inverse sine function here $\sin^{-1}()$ is also known as arcsin.

By the law of cosine,

$c^{2} = a^{2} + b^{2} - 2\;a\cdot b\cdot \cos{C}$ ,

where

$a$ , $b$ , and $c$ are the lengths of sides of triangle ABC, and
$\cos{C}$ is the cosine of angle C.

For triangle ABC:

$b = 21$ ,
$c = 30$ ,
The length of $a$ (segment BC) is to be found, and
The cosine of angle A is $\cos{123\textdegree}$ .

Therefore, replace C in the equation with A, and the law of cosine will become:

$a^{2} = b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}$ .

$\displaystyle \begin{aligned}a &= \sqrt{b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}}\\&=\sqrt{21^{2} + 30^{2} - 2\times 21\times 30 \times \cos{123\textdegree}}\\&=45.0 \end{aligned}$ .

For triangle ABC:

$a = 14$ ,
$b = 9$ ,
$c = 6$ , and
Angle B is to be found.

Start by finding the cosine of angle B. Apply the law of cosine.

$b^{2} = a^{2} + c^{2} - 2\;a\cdot c\cdot \cos{B}$ .

$\displaystyle \cos{B} = \frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}$ .

$\displaystyle B = \cos^{-1}{\left(\frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}\right)} = \cos^{-1}{\left(\frac{14^{2} + 6^{2} - 9^{2}}{2\times 14\times 6}\right)} = 26.0\textdegree$ .

For triangle DEF:

The length of segment DF is to be found,
The length of segment EF is 9,
The sine of angle E is $\sin{64\textdegree}}$ , and
The sine of angle D is $\sin{39\textdegree}$ .

Apply the law of sine:

$\displaystyle \frac{DF}{EF} = \frac{\sin{E}}{\sin{D}}$

$\displaystyle DF = \frac{\sin{E}}{\sin{D}}\cdot EF = \frac{\sin{64\textdegree}}{39\textdegree} \times 9 = 12.9$ .

7 0

3 years ago

Each face of a six-sided cube is painted a different color. The cube is rolled twice and a coin is flipped. How many different p

Lostsunrise [7]

72 possible outcomes

8 0

3 years ago

Read 2 more answers

Solve the equation<br> -5=y for x.

sesenic [268]

Answer: 5 = y

Step-by-step explanation:

7 0

3 years ago

The domain of the following relation R {(3, −2), (1, 2), (−1, −4), (−1, 2)} is

LUCKY_DIMON [66]

Given:
3, -2
1, 2
-1, -4
-1, 2

The format is (x,y)

The domain is all the x-values while range is all the y-values.

domain: (3,1, -1,-1) 2nd option given.

4 0

3 years ago