All categories

3 years ago

Clard graphed her reading fluenoy

Mathematics

1 answer:

Digiron [165]3 years ago

3 0

Answer:

100

Step-by-step explanation:

To find mean/average you add all of them together, then divide by however number there are.

99+88+97+107+100+109 = 600/6 = 100

You might be interested in

Darcie wants to crochet a minimum of 3 blankets blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 of a

bearhunter [10]

Answer:

The inequality to determine the number of days, $s$ , Darcie can skip crocheting and still meet her goal is:

$s\leq 15$

Thus, Darcie can skip a maximum of 15 days.

Step-by-step explanation:

Question

Darcie wants to crochet a minimum of 3 blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 of a blanket per day. She has 60 days until when she wants to donate the blankets, but she also wants to skip crocheting some days so she can volunteer in other ways. Write an inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal.

Given:

Darcie has a target to crochet a minimum of 3 blankets.

Rate at which Darcie crochets = $\frac{1}{15}$ of a blanket per day.

Darcie has 60 days to crochet the blankets

To write an inequality to determine the number of days, $s$ , Darcie can skip crocheting and still meet her goal.

Solution:

The number of days Darcie can skip crocheting is represented by $s$

So, number of days left for Darcie to crochet = $60-s$

In 1 day Darcie crochets $\frac{1}{15}$ of a blanket.

So, in $(60-s)$ days she will crochet = $\frac{1}{15}(60-s)$ blankets.

Her aim is to crochet at least 3 blankets.

Thus, the inequality can be given as:

$\frac{1}{15}(60-s)\geq 3$

Solving for $s$

Multiplying both sides by 15 to remove fractions.

$15\times\frac{1}{15}(60-s)\geq 3\times 15$

$60-s\geq 45$

Subtracting both sides by 60.

$60-60-s\geq 45-60$

$-s\geq -15$

Dividing both sides by -1.

$\frac{-s}{-1}\leq \frac{-15}{-1}$ [ On dividing by negative number the sign of the inequality is reversed]

∴ $s\leq 15$

Thus, Darcie can skip a maximum of 15 days.

3 0

3 years ago

Read 2 more answers

A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values

mamaluj [8]

Answer:

Systolic variation coefficient (CVS) = 0.1446 = 14.46%

Diastolic variation coefficient (CVD) = 0.1789 = 17.89%

The variation, with respect to the mean, of the systolic pressure sample is slightly less than the variation of the Diastolic pressures.

Step-by-step explanation:

Systolic Mean (MS) = 127.8

Diastolic Mean (MD) = 73.5

Standard Deviation Systolic (sdS) = 18,486

Standard Deviation Diastolic (sdD) = 13.1508

The coefficient of variation is defined by:

Systolic variation coefficient (CVS) = sdS / MS = 18.486 / 127.8 = 0.1446 = 14.46%

Diastolic variation coefficient (CVD) = sdD / MD = 13.1508 / 73.5 = 0.1789 = 17.89%

Then, it can be concluded that the variation, with respect to the mean, of the systolic pressure sample is slightly less than the variation of the Diastolic pressures.

8 0

3 years ago

Simplify. 11 3/4 - 8 1/2 A. 3 1/4 B. 3 1/3 C. 4 1/4

Rainbow [258]

Answer:

Step-by-step explanation:

11 3/4 - 8 1/2 = 3 1/4

5 0

3 years ago

Factor the trigonometric equation.<br> cos2x-cosx

prisoha [69]

Cos(2x) = cos^2(x) - sin^2(x) - cos(x)

but sin^2(x) = 1 - cos^2(x)

cos(2x) - cos(x) = cos^2(x) - (1 - cos^2(x) ) - cos(x)

cos(2x) - cos(x) = cos^2(x) - 1 + cos^2(x) - cos(x)

cos(2x) - cos(x) = 2cos^2(x) - 1 - cos(x)

cos(2x) - cos(x) = (2cos(x) + 1)(cos(x) - 1)

I think this is what you have asked for.

4 0

3 years ago

Graph the line passing through (−2,5) whose slope is m=1/5

Nonamiya [84]

Hello there! :)

Given:

x-coordinate of point = -2

y-coordinate of point = 5

Slope, or "m" = 1/5

Substitute in these values into slope-intercept formula (y = mx+b)

5 = 1/5(-2) + b

5 = -2/5 + b

25/5 = -2/5 + b

27/5 = b

Rewrite the equation:

y = 1/5x + 27/5

Graph the equation using a graphing utility:

4 0

3 years ago

Read 2 more answers