<h3>Explanation:</h3>
GCF: the greatest common factor of numerator and denominator is a factor that can be removed to reduce the fraction.
<em>Example</em>
The numerator and denominator of 6/8 have GCF of 2:
6/8 = (2·3)/(2·4)
The fraction can be reduced by canceling those factors.
(2·3)/(2·4) = (2/2)·(3/4) = 1·(3/4) = 3/4
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LCM: the least common multiple of the denominators is suitable as a common denominator. Addition and subtraction are easily performed on the numerators when the denominator is common.
<em>Example</em>
The fractions 2/3 and 1/5 can be added using a common denominator of LCM(3, 5) = 15.
2/3 + 1/5 = 10/15 + 3/15 = (10+3)/15 = 13/15
I think the answer is C hope this would help you
Answer:
Therefore, the volume of the cone is V=4π.
Step-by-step explanation:
From task we have a circular cone with radius 2 m and height 3 m. We use the disk method to find the volume of this cone.
We have the formula:
We know that r=2 and h=3, and we get:
![V=\int_0^3\pi \cdot \left(\frac{2}{3}x\right)^2\, dx\\\\V=\int_0^3 \pi \frac{4}{9}x^2\, dx\\\\V= \frac{4\pi}{9} \int_0^3 x^2\, dx\\\\V= \frac{4\pi}{9} \left[\frac{x^3}{3}\right]_0^3\, dx\\\\V= \frac{4\pi}{9}\cdot 9\\\\V=4\pi](https://tex.z-dn.net/?f=V%3D%5Cint_0%5E3%5Cpi%20%5Ccdot%20%5Cleft%28%5Cfrac%7B2%7D%7B3%7Dx%5Cright%29%5E2%5C%2C%20dx%5C%5C%5C%5CV%3D%5Cint_0%5E3%20%5Cpi%20%5Cfrac%7B4%7D%7B9%7Dx%5E2%5C%2C%20dx%5C%5C%5C%5CV%3D%20%5Cfrac%7B4%5Cpi%7D%7B9%7D%20%5Cint_0%5E3%20x%5E2%5C%2C%20dx%5C%5C%5C%5CV%3D%20%5Cfrac%7B4%5Cpi%7D%7B9%7D%20%5Cleft%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%5Cright%5D_0%5E3%5C%2C%20dx%5C%5C%5C%5CV%3D%20%5Cfrac%7B4%5Cpi%7D%7B9%7D%5Ccdot%209%5C%5C%5C%5CV%3D4%5Cpi)
Therefore, the volume of the cone is V=4π.
3/5 and 6/8 are not proportional as even though 3 goes into 6 evenly, 5 does not go into 8 evenly so that makes it disproportional.
