The statements aren't given; however the number of 1/2 and 1/4 - pound package have been calculated below.
Answer:
Step-by-step explanation:
Given :
A 12 pound block :
Number of 1/2 pound packages that can be obtained :
12 ÷ 1/2 ;
12 * 2/1 = 24 (1/2 - Pound package) can be obtained.
Number of 1/4 pound package that can be obtained :
12 ÷ 1/4
12 * 4 /1 = 48 (1/4 - Pound package) can be obtained
We can obtain twice the number of 1/2 - pound package by using the 1/4 - pound slicing.
For
to be continuous at
, we need to have
Note that
means that
, but that
is *approaching* 5. We're told that for
, we have
We can write
and the limit would be
and so
is discontinuous.
Solution:
Given:
when a = 4, substitute for a in the expression;
Therefore, if (a = 4), then
Hence, the answer is 16.
4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
We are going to rewrite both numbers:
(4.2 × 10 ^ 6) = 4200000
(2.25 × 10 ^ 5) = 225000
Adding we have:
4200000 + 225000 = 4425000
Rewriting in exponential notation we have:
4425000 = 4,425 * 10 ^ 6
Answer:
(4.2 × 10 ^ 6) + (2.25 × 10 ^ 5) is equal to:
4,425 * 10 ^ 6
