We can use quadratic formula to determine the roots of the given quadratic equation.
The quadratic formula is:
b = coefficient of x term = -11
a = coefficient of squared term = 2
c = constant term = 15
Using the values, we get:
So, the correct answer to this question are option B and D
Answer:
Step-by-step explanation:
This number should be 10.
The tens digit the the 1st number on a two-digit number. Because the highest number you can go without creating a hundredths place is a 9, and the question says the ones-place (the last digit), this has to make this number 0. If it were to be 1 or anything higher, it would have to create a hundredths place if the rule of the question were to be followed.
Example:
If ones-place were 1, then following rule: 1+9 = 10
Your number would end up being 101 instead of a tenths place number.
I hope that made some sense somewhere!
Step-by-step explanation:
a.
Let's give the starting amount of water as s. Every minute, 2 inches of water are lost, meaning that given the starting amount, s, we subtract 2 inches from s every minute, so s - 2 every minute = height of water left, so s - 2t (t representing minutes) = h
To figure out s, we simply plug our known value -- 9 minutes in and 11 inches left. s - 2(9) = 11, s-18=11, s= 29
29 - 2t = h
b. We know that we cannot have negative minutes, so the minimum amount of time that makes sense is 0. To figure out the maximum, we stop counting how much time has occurred when there is no water left, so we have to figure out when h = 0
29-2t = h = 0
t=14.5
Therefore, anything between 0 and 14.5 minutes makes sense
c. Anything between 0 and 29 makes sense because the height of water cannot be negative and we cannot get higher than the starting amount
By working backwards,
<span>you get 76 as your answer because you have to remove the rightmost digit, right? so the three-digit number is </span>
<span>76x </span>
<span>(x stands for the rightmost digit, because we don't know what the rightmost digit is) </span>
<span>we are told we have to add six to the three digit number to get 76x, so we have to subtract 6 from 76x: </span>
<span>76x - 6 = ??? </span>
<span>since we assume that the original two-digit number is NOT 76, and any number from 760 to 765 inclusive minus 6 is logically in the 750-range, we can conclude that the original two-digit number is 75. </span>
