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Molodets [167]
3 years ago
6

A circle has its Center at (-2, 5) and a radius of 4 units. What is the equation of the circle?

Mathematics
1 answer:
Artist 52 [7]3 years ago
8 0
\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{-2}{ h},\stackrel{5}{ k})\qquad \qquad 
radius=\stackrel{4}{ r}
\\\\\\\
[x-(-2)]^2+[y-5]^2=4^2\implies (x+2)^2+(y-5)^2=16
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Is it a multiple choise?

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Find the equation (in standard form) whose center is (5, -3) and goes through (2, 5).
yanalaym [24]
We can write this as

(x - 5)^2 + (y + 3)^2 = r^2

where r = radius

Plugging in the point (2,5) we have

(2-5)^2 + (5+3)^2 = r^2
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so the required equation is

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3 0
3 years ago
How do you do this?
lora16 [44]
X/5 = 24/8
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x/5 = 3

x = 5*3 = 15 Answer

a/27 = 8/24 = 1/3 
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6 0
3 years ago
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Ann [662]

Answer:

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Step-by-step explanation:

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Just multiply 3 by both of the numbers inside the parentheses and we get: 3u-15

4 0
3 years ago
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Please answer if you can 30 points.
Rudik [331]

Answer:

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