All categories

3 years ago

How many solutions does the system have?

Mathematics

2 answers:

elena-s [515]3 years ago

8 0

Answer:

The answer is one solution

Step-by-step explanation:

I tried it on khan and it was correct.

Alexeev081 [22]3 years ago

6 0

Answer: one solution

Step-by-step explanation:

The two lines have different slopes, so they can't be the same line (infinitely many solutions) or parallel (no solutions). The lines intersect at

3x+3 = -2x - 4

5x = -7

x = -7/5

3(-7/5) + 3 = -2(-7/5) - 4

-21 + 15 = 14 - 20

-6 = -6

You might be interested in

PLEASE HELP ASAP ASAP URGENT WILL GIVE BRAINLIEST

Luden [163]

Answer:

for the solve and check:

$2\frac{3}{8}+x=3\frac{1}{4} \\2\frac{3}{8}-2\frac{3}{8}+x=3\frac{1}{4}-2\frac{3}{8}\\\\x=3\frac{1}{4}-2\frac{3}{8}\\\\\\x=\frac{7}{8}$

----------------------------------------------------

$3\frac{3}{8}+x=4\frac{1}{4} \\3\frac{3}{8}-3\frac{3}{8}+x=4\frac{1}{4}-3\frac{3}{8}\\\\x=4\frac{1}{4}-3\frac{3}{8}\\\\\\x=\frac{7}{8}$

for the second solve and check:

$4\frac{3}{8}+x=5\frac{1}{4} \\4\frac{3}{8}-4\frac{3}{8}+x=5\frac{1}{4}-4\frac{3}{8}\\\\x=5\frac{1}{4}-4\frac{3}{8}\\\\\\x=\frac{7}{8}$

----------------------------------------------------

$5\frac{3}{8}+x=6\frac{1}{4} \\5\frac{3}{8}-5\frac{3}{8}+x=6\frac{1}{4}-5\frac{3}{8}\\\\x=6\frac{1}{4}-5\frac{3}{8}\\\\\\x=\frac{7}{8}$

8 0

3 years ago

Read 2 more answers

NEED HELP ASAP., <br><br> WILL GIVE BRAINLIEST

kow [346]

The answer is 9 1/2

6 0

3 years ago

Read 2 more answers

Jack rented a moving truck for 7 hours and paid $153.65. how much did it cost per hour?

rosijanka [135]

Answer:

$21.95 per hour

Step-by-step explanation:

To find the cost per hour, we take the total cost and divide by the number of hours

$153.65/ 7 hours

$21.95 per hour

7 0

3 years ago

Drag each title to the correct box. Not all tiles will be used

mestny [16]

Answer:

4, 1, 6.

See explanation

Step-by-step explanation:

You are given the equation

$d=vt-\dfrac{1}{2}at^2$

First subtract $vt$ from both sides:

$d-vt--\dfrac{1}{2}at^2$

and multiply the equation by -1:

$vt-d=\dfrac{1}{2}at^2\ \ \ \ (1)$

Now multiply (1) by 2:

$2(vt-d)=at^2\ \ \ \ \ (2)$

At last, divide by $a$

$t^2=\dfrac{2(vt-d)}{a}\ \ \ \ \ (3)$

5 0

3 years ago

Kate collected a sample of monthly rents and recorded the following numbers:

d1i1m1o1n [39]

C) will not effected (the most frequent is still 600$)

8 0

3 years ago