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3 years ago

Describe Cullen's mistake

Mathematics

2 answers:

gizmo_the_mogwai [7]3 years ago

8 0

Answer:Cullen did not add 4n to the -6n he added -4n.

Step-by-step explanation:When you go to move the -4n you want to add 4n to make the -4n turn to 0. This is because we need n on one side and what it is equaled to on the other.

Deffense [45]3 years ago

5 0

He did not add 4n that is crucial to the problem

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Write each percent as a fraction in simplest form 45 1/2%

Oksanka [162]

$45 \frac{1}{2} \%$
to improper fraction gives
$\frac{91}{2} \%$
so to fraction, we divide by 100
$\frac{91}{2} \div 100$
$\frac{91 }{2} \times \frac{1}{100}$
so the answer should be
$\frac{91}{200}$

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4 years ago

Ms Adams shares out 21 pencils between Niamah and Jack in the ratio 2:5 how many pencils does each child get

aleksklad [387]

Answer:

niamah : jack

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3 years ago

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Solve for x and graph: <br> show your work!<br><br> -9x -30 < 15?

GarryVolchara [31]

-9x - 30 < 15
<u>      + 30 + 30</u>
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3 years ago

Read 2 more answers

Mel<br> used partial quotients to divide 145 by 5. What can be a partial quotient?

nlexa [21]

Answer:

Answer will be 29.

Step-by-step explanation:

When you divide 145 by 5 that is:

145/5 = 29

29 can't be divided further.

Hence partial quotient will be 29 here.

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3 years ago

The following system has a solution: x=10, y=-3, z=14

wolverine [178]

<h2>Answer:</h2><h3>False</h3>

<h2>Step-by-step explanation:</h2>

In this problem, we have the following System of Three Equations in Three Variables, so our goal is to determine whether $x=10, \ y=-3, \ z=14$ is the solution to this system, that is, the ordered triple $P(x,y,z)$ where three planes intersect.

The easier way to find the answer is to plug in the x, y and z values in the equations and figure out whether the equations satisfy the solutions. Then:

$First \ Equation: \\ \\ 3(10)+7(-3)-14=-5 \\ \\ It \ satisfies \ the \ first \ equation \\ \\ \\ Second \ Equation: \\ \\ 9(10)-(-3)-4(14)=37 \neq 17 \\ \\ It \ doesn't \ satisfy \ the \ second \ equation$

STOP HERE! Since the x, y an z values doesn't satisfy the second equation, the $x=10, \ y=-3, \ z=14$ is not the solution to the system of equations.

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3 years ago