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muminat
3 years ago
10

Here are the total scores of 10 students in an introductory statistics course.

Mathematics
1 answer:
cestrela7 [59]3 years ago
4 0

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Mean (m) = 72

Standard deviation (sd) = 10

Grading cutoff policy:

bottom 5% receive F

next 15% receive D

next 35% receive C

next 30% receive B

A) Give the cutoffs for the grades in this course in terms of standardized scores.

Standardized score for grade cutoff:

Locating the Zscore for the proportions on the z table :

Bottom 5% = 0.05 ; corresponding Zscore = - 1.645

next 15% receive D = (5 +15)% 0.20 ; corresponding Zscore = - 0.84

next 35% receive C = (20+35)% = 0.55 ; corresponding Zscore = 0.13

next 30% receive B = (55 + 30)% = 0.85 ; Corresponding Zscore = 1.04

B) Give the cutoffs in terms of actual total scores.

Recall:

Zscore = (x - m) /sd ; where x = actual score

x = sd*z + m

For F:

10*(-1.645) + 72 = 55.55

For D:

10*(-0.84) + 72 = 63.6

For C:

10*(0.13) + 72 = 73.3

For B:

10*(1.04) + 72 = 82.4

C) Do you think that this method of assigning grades is a good one?

Yes, it is good in terms of expressing scores around the mean such that score below are negative and those above are positive. However, it is a little bit ambiguous.

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w + (-x) - 2/3

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The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista
baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{10.634 - \mu}{\sigma}

10.634 - \mu = 1.28\sigma

\mu = 10.634 - 1.28\sigma

5% having a resistance smaller than 9.7565 ohms.

This means that when X = 9.7565, Z has a pvalue of 0.05. So when X = 9.7565, Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{9.7565 - \mu}{\sigma}

9.7565 - \mu = -1.96\sigma

\mu = 9.7565 + 1.96\sigma

We also have that:

\mu = 10.634 - 1.28\sigma

So

10.634 - 1.28\sigma = 9.7565 + 1.96\sigma

1.96\sigma + 1.28\sigma = 10.645 - 9.7565

3.24\sigma = 0.8885

\sigma = \frac{0.8885}{3.24}

\sigma = 0.2742

The mean is

\mu = 10.634 - 1.28\sigma = 10 - 1.28*0.2742 = 9.65

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

8 0
4 years ago
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