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Schach [20]
3 years ago
13

When building a house, the number of days required to build varies inversely with with the number of workers. One house was buil

t in 19 days by 35 workers. How many days would it take to build a similar house with 5 workers?
Mathematics
1 answer:
Helga [31]3 years ago
5 0

Let d represent number of days and n represent number of workers.

We have been given that when building a house, the number of days required to build varies inversely with with the number of workers.

We know that the equation y=\frac{k}{x} represents the relation where y is inversely proportional to x and k is the constant of proportionality.  

So our required equation would be d=\frac{k}{n}

Upon substituting our given values, we will get:

19=\frac{k}{35}

k=19\cdot 35

k=665

Since constant of proportionality is 665, so our equation would be d=\frac{665}{n}.

To find the number of days it will take to build a similar house with 5 workers, we will substitute n=5 in our equation as:

d=\frac{665}{5}

d=133

Therefore, it will take 133 days for 5 workers to build a similar house.

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Sin60 =b/10
<span>√3/2 = b/10
</span>b = <span>√3 / 2 (10)
</span>b = 5<span>√3
</span>
d^2  = 10^2 - (5√3)^2
d^2 = 100 - 75
d^2 = 25
d = 5

sin30 = b/a
1/2 = 5√3  / a

a = 5√3 (2)
a = 10√3

c^2 = (10√3)^2  -  (5√3)^2
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c = 15

so
a =10√3,  b = 5√3, c = 15,d = 5
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