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VARVARA [1.3K]
3 years ago
11

Baileigh is using a piece of string to hang a painting on the wall. The back of the painting is diagrammed below. 12 cm 12 cm 5

cm 5 cm Note: Figure is not drawn to scale. What is the length of the string? A. 13 centimeters B. 26 centimeters C. 17 centimeters D. 34 centimeters Reset Next Question
Mathematics
1 answer:
Nutka1998 [239]3 years ago
6 0
HI THE ANSWER IS 26CM

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Please help me with parts A, B, and C.
leonid [27]

Answer:

  (a) scalene, see attachment

  (b) acute, see attachment

  (c) correct; isosceles

Step-by-step explanation:

(a) The sides of the triangle all have different lengths, so the triangle is scalene. Differences in coordinates between the points of the triangle are (6, 2), (5, 2), and (4, 1), so no two distances between these points can be the same.

__

(b) The angle opposite the longest side is clearly an acute angle, so the triangle is an acute triangle.

__

(c) Miles and Brad live on the same north/south line. Jose lives at a distance that is halfway between those houses in the north-south direction. Hence the distance to Miles' and Brad's houses must be the same from Jose's house. That means the triangle connecting Miles', Brad's, and Jose's houses will be an isosceles triangle.

4 0
3 years ago
A bottle of window cleaner is $3.99. It is on sale for 10% off and you can save an additional 5% using your credit card. What is
wariber [46]
If I did the math correct, the answer is C: 3.63
8 0
2 years ago
Read 2 more answers
A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet
gayaneshka [121]

Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

h(x)=10+0.1(x^{1.5})

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

h'(x)=0.1(1.5)x^{0.5}=0.15x^{0.5}

s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx

s=2\int_{0}^{17.5}\sqrt{1+(0.15x^{0.5})^2}dx

s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx

Let 1+0.0225x=t

dx=\frac{1}{0.0225}dt

s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt

s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}

s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}

s=\frac{4}{3\times 0.0225}((1+0.0225(17.5))^{\frac{3}{2}-1)

s=28.21

Weight of cable=28.21\times 10.4=293.38pound

8 0
3 years ago
What is 2/3 - 8/12 please help me understand this :)
ANEK [815]
You times the denominator from 2/3 by 4 so it can be equivalent to 8/12
2/3 x 4 = 8/12-8/12=0
3 0
3 years ago
Read 2 more answers
A jar contains 46 quarters and pennies. The total value of the coins is $4.30. Which system of equations can be used to find p,
Crazy boy [7]

Answer:

16 quarters

30 pennies

Step-by-step explanation:

q= quarters

p=pennies

set up a system of equations. One equation is for total value, the other is total # of coins.

q + p = 46

0.25q + 0.01p = 4.30 -> multiply this equation by 4 so you can subtract from the top equation

q + P =46

1q + 0.04p = 17.20

subtract the bottom equation from the top

0.96p = 28.8

divide by 0.96

p=30

substitute p in the top equation

q + 30 = 46

subtract 30 from both sides

q = 16

4 0
3 years ago
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