Answer:
(a) scalene, see attachment
(b) acute, see attachment
(c) correct; isosceles
Step-by-step explanation:
(a) The sides of the triangle all have different lengths, so the triangle is scalene. Differences in coordinates between the points of the triangle are (6, 2), (5, 2), and (4, 1), so no two distances between these points can be the same.
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(b) The angle opposite the longest side is clearly an acute angle, so the triangle is an acute triangle.
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(c) Miles and Brad live on the same north/south line. Jose lives at a distance that is halfway between those houses in the north-south direction. Hence the distance to Miles' and Brad's houses must be the same from Jose's house. That means the triangle connecting Miles', Brad's, and Jose's houses will be an isosceles triangle.
Answer:
293.38 pounds
Step-by-step explanation:
We are given that
Distance between poles=35 feet

Weight of cable=10.4 per linear foot
We have to find the weight of the cable.
Differentiate w.r.t




Let 


![s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B2%7D%7B0.0225%7D%5Ctimes%5Cfrac%7B2%7D%7B3%7D%5Bt%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%5D%5E%7B17.5%7D_%7B0%7D)
![s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}](https://tex.z-dn.net/?f=s%3D2%5Ctimes%20%5Cfrac%7B2%7D%7B3%5Ctimes0.0225%7D%5B%281%2B0.0255x%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%5D%5E%7B17.5%7D_%7B0%7D)

s=28.21
Weight of cable=
pound
You times the denominator from 2/3 by 4 so it can be equivalent to 8/12
2/3 x 4 = 8/12-8/12=0
Answer:
16 quarters
30 pennies
Step-by-step explanation:
q= quarters
p=pennies
set up a system of equations. One equation is for total value, the other is total # of coins.
q + p = 46
0.25q + 0.01p = 4.30 -> multiply this equation by 4 so you can subtract from the top equation
q + P =46
1q + 0.04p = 17.20
subtract the bottom equation from the top
0.96p = 28.8
divide by 0.96
p=30
substitute p in the top equation
q + 30 = 46
subtract 30 from both sides
q = 16