Shaunee won 79 tickets at Chuck e' Cheese's. She
2 answers:
Answer:
Step-by-step explanation:
From the problem statement, we can set up the following equation:
where is the number of tickets each friend got, and
is the number of tickets that Shaunee got. We know that Shaunee got 25, so we know
and can plug that into the equation:
Subtracting 25 from each side gives us the following:
Dividing both sides by 3 gives us the answer:
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Answer:
is an attachment
test statistic = 9.87
p value is less than 0.01
Not all means of the three assembly methods are equal
Step-by-step explanation:
the anova table is an attachment
total number of methods = k = 3
number of observations n = 30
for treatment, df = 3-1 = 2
for error, df = 30 -3 (n-k) = 27
sst = 10800, sstr = 4560, sse = 10800-4560 = 6240
we find the mean of squares for error
sse/df of error = 6240/27 = 231.11
mean of squares for treatment = 4560/2 = 2280
test stat
F = 2280/231.11
= 9.8654
using f distribution table;
alpha = 0.05
df = 2 , 27
we get 3.35
h0; no difference in mean
h1; there is difference
9.87 > 3.35 so we reject H0, there is difference in means. all are not equal.
pvalue calculation
using excel,
FDIST(9.8654, 2, 27) = 0.0006078
p value is less than 0.01
we conclude that a. Not all means of the three assembly methods are equal
