9514 1404 393
Answer:
(b) 5, 17
Step-by-step explanation:
You can try the answer choices easily enough.
2 +3×8 ≠ 14
2 +3×5 = 17 . . . . this choice works (5, 17)
2 +3×2 ≠ 20
2 +3×4 ≠ 18
2 +3×10 ≠ 12
__
Or, you can solve the equation:
x + (2 +3x) = 22
4x = 20 . . . . . . . . subtract 2
x = 5 . . . . . . . . . . divide by 4
The numbers are 5 and (22 -5) = 17.
Answer:
Step-by-step explanation:
10+6n=n-5
6n-n=-5-10
5n=-15
n=-3
Answer:
Discount= $4.94
Final Price= $28.04
Step-by-step explanation:
Discount = original price x discount / 100
Discount= 32.99 x 15/ 100
Discount= 494.85/ 100
You save= $4.9485 ($494)
Final Price= original price - discount
Final Price= 32.99 - 4.9485
Final Price= $28.04
The graph Plot of the given results shown represents; A relation only
<h3>How to interpret a scatter plot?</h3>
For it to be a function, then no x-value can produce more than 2 y-values. However, we see that at x = 25, y has 2 values. Similarly, at x = 15, y has two values.
Thus, the graph plot can only be a relation as it is not a function as seen from the points plotted in the graph.
The complete question is;
Mrs. Anderton is giving a test in her third-period class. She has decided to record the amount of time that each student takes to finish the test (in minutes) and compare that to the grade each student receives on the test (out of 100). A plot of her results is below. Which of the following does this situation represent?
A. both a relation and a function
B. a function only
C. neither a relation nor a function
D. a relation only
Read more about Scatter Plot at; brainly.com/question/6592115
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Answer:
They'll meet after 200 meters , if they simultaneously start running towards each other.
Step-by-step explanation:
Let x =distance travelled by dog and 200-x be the distance travelled by cat. Inorder to meet, the sum of their travelled distances shall be equal to 200 meters as they are far apart by 200 meters.
Dog: Distance =Speed x time: x=30t
Cat: Distance = 200-x
=24t
The sum of their distance travelled shall be 200 meters: 30t+ 24t= 200;54t=200;t=200/54=3.7secs
So they will meet after 3.7 seconds
To check:
Distance travelled by dog :x=30(3.7)
=111.11 meters
Distance travelled by cat: 24t=24(3.7)
=88.89 meters
Therefore since they are travelling towards each other and their distance apart is 200 meters, after 3.7 seconds they will meet because dog travelled 111.11 meters and cat travelled 88.89 meters and they covered already 200 meters as the sum of 111.11+ 88.89
=200 meters
