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2 years ago

Please explain this and help me

Mathematics

1 answer:

suter [353]2 years ago

8 0

Juan rode the slowest. It took him 5 minutes to go 2 blocks and another 3 minutes to go 2 more blocks. It was taking him longer minutes to go 2 blocks at a time. Took Juan 17 minutes to do 8 blocks and Rita did 8 blocks in 8 minutes she was faster. Hope this helps

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5. Graph the given system of linear inequalities on the coordinate plane below. (2 points)sy <-3x - 4< 21-15NA11 2 3 4 5 6

xxTIMURxx [149]

ANSWERS

(5) Graph:

(6) Solutions: (-1, -5) and (-2, -7)

Not solutions: (1, 1) and (-4, -3)

EXPLANATION

(5) To graph this system, first, we have to graph each of the inequalities. Both are linear, so we have to graph each line with a dashed line - this is because they are "less than" the line, so the line is not included, and shade the area below each of them.

The first inequality is y < -3x-4,

The second inequality is y < 2x - 1,

The graph of the system is the area shared by both graphs,

(6) Any point that is inside the shaded area is a solution of the system. For example, points (-1, -5) and (-2,-7) are solutions to the system.

On the other hand, any point outside that area, or on the dashed lines is not a solution. For example, points (1, 1) and (-4, -3) are not solutions

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8 months ago

How would you express the area of the rectangle using the Distributive Property?

andreyandreev [35.5K]

Answer:

The area of the rectangle can be found using two different expressions: a(b + c) or ab + ac. The equality of these expressions, a(b + c) = ab + ac, is the distributive property.

5 0

2 years ago

Read 2 more answers

What is the value of a in A-17/3=-20?

Rina8888 [55]

$\dfrac{A-17}{3}=-20\qquad|\cdot3\\\\A-17=-60\qquad|+17\\\\A=-43$

$A-\dfrac{17}{3}=-20\\\\A-\dfrac{17}{3}=\dfrac{-60}{3}\qquad|+\dfrac{17}{3}\\\\A=-\dfrac{43}{3}$

4 0

3 years ago

45% into a fraction simplest form

Aliun [14]

9/20

45% is 0.45. To switch into a fraction you do 45 over 100, simplified is 9/20.

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2 years ago

Four equivalent forms of a quadratic function are given. Which form displays the zeros of function h?

taurus [48]

Step-by-step explanation:

As we know that $f$ is a polynomial function, the values of $x$ for which $f(x)=0$ are said to be the zeros of $f$ .

Factoring the polynomial equation, if it is eligible to get factored, setting each factor equal to zero and solving can determine the zeros.

So, it is clear from above that option A i.e. $h\left(x\right)=-4\left(x\:-\:2\right)\left(x\:+\:2\right)$ and option C i.e. $h\left(x\right)\:=\:4\left(x^2\:-\:4\right)$ displays the zeros of function h, as they can be factored by setting each factor equal to zero.

Option A)

Lets solve them to get the zeros of these functions.

Considering the function

$h\left(x\right)=-4\left(x\:-\:2\right)\left(x\:+\:2\right)$

$\mathrm{The\:roots\:are\:the\:intercepts\:with\:the\:x-axis}\:\left(y=0\right)$

$-4\left(x-2\right)\left(x+2\right)=0$

Using the Zero Factor Principle:

$\mathrm{ \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$\mathrm{Solve\:}\:x-2=0:\quad x=2$

$\mathrm{Solve\:}\:x+2=0:\quad x=-2$

$\mathrm{The\:zeros\:to\:the\:quadratic\:equation\:are:}$

$x=2,\:x=-2$

Option B)

Considering the function

$h\left(x\right)\:=\:4\left(x^2\:-\:4\right)$

$\mathrm{The\:roots\:are\:the\:intercepts\:with\:the\:x-axis}\:\left(y=0\right)$

$4\left(x^2-4\right)=0$

$\mathrm{Divide\:both\:sides\:by\:}4$

$\frac{4\left(x^2-4\right)}{4}=\frac{0}{4}$

$x^2-4=0$

$x^2=4$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=\sqrt{4},\:x=-\sqrt{4}$

$x=2,\:x=-2$

Although the zeros of the function $h\left(x\right)=-4x^2\:+\:16$ can also be obtained for the function by similar method. But, for this we would have to solve them before determining the zeros.