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Lorico [155]
2 years ago
7

If Wendell creates a scale drawing using the scale 1 inch to 10 feet, what will the dimensions of the deck in the scale drawing

be?
Mathematics
2 answers:
leonid [27]2 years ago
3 0

Answer:

You did not send a picture, so here is how you generally do it.

12 inches is 1 foot, and if you want to scale to be 1 inch to 10 feet it should be 10 times that, so 12 * 10 = 120. The scale is 120. Multiply the dimensions of the deck by 120 for your answer.

Goryan [66]2 years ago
3 0
There is no picture sorry I can’t help :)
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HELP{
sertanlavr [38]

Answer: The correct conclusion is(B) The functions f(x) and g(x) are reflections over the y-axis.

Step-by-step explanation: Two functions f(x) and g(x) are given as follows:

f(x)=2^x,~~~~~~~g(x)=\left(\dfrac{1}{2}\right)^x.

We know that if f(-x) = g(x), then the functions are reflections over Y-axis and if - f(x) = g(x), then the functions are reflections over X-axis.

We have,

f(-x)=2^{-x}=\left(\dfrac{1}{2}\right)^x=g(x),\\\\-f(x)=-2^x\neq g(x).

So, the function g(x) is a reflection of f(x) over Y-axis.

The graph of f(x) and g(x) are drawn in the attached file. From there, it is clear that the functions are reflections over Y-axis, not reflections over X-axis.

So, options (A) is incorrect and option (B) is correct.

From the table, we have

f(-2)=\dfrac{1}{4},~~f(-1)=\dfrac{1}{2},~~f(0)=1,~~f(1)=2,~~f(2)=4,\\\\g(-2)=4,~~g(-1)=2,~~g(0)=1,~~g(1)=\dfrac{1}{2},~~g(2)=\dfrac{1}{4}.

So, as the value of 'x' increases, the value of f(x) increases and value of y(x) decreases.

Therefore, f(x) is an increasing function and g(x) is a decreasing function. So, option (C) is incorrect.

Also, we have

f(0)=g(0)=1.

So, both the functions have same initial value. So, option (D) is also incorrect.

Thus, the correct conclusion is (B) The functions f(x) and g(x) are reflections over the y-axis.

4 0
3 years ago
Read 2 more answers
The optimum diameter d (in millimeters) of the pinhole in a pinhole camera can be modeled by d=1.9[(5.5×10−4)L]1/2, where is the
amid [387]

The optimum pinhole diameter for a camera box with a length of 10 centimeters is 0.446 mm

<h3><u>Solution:</u></h3>

Given that,

<h3><u>The optimum diameter d (in millimeters) of the pinhole in a pinhole camera can be modeled by:</u></h3>

d = 1.9[(5.5 \times 10^{-4})l]^{\frac{1}{2}}

where l is the length (in millimeters) of the camera box

<h3><u>Find the optimum pinhole diameter for a camera box with a length of 10 centimeters</u></h3>

l = 10 cm

We know that,

10 cm = 100 mm

<em><u>Therefore, plug in l = 100 in given formula</u></em>

d = 1.9[(5.5 \times 10^{-4}) \times 100]^{\frac{1}{2}}\\\\d = 1.9[5.5 \times 10^{-4} \times 10^2]^{\frac{1}{2}}\\\\d = 1.9[5.5 \times 10^{-2}]^{\frac{1}{2}}\\\\d = 1.9 \times 5.5^{\frac{1}{2} \times 10^{-1}}\\\\d = 0.19 \times 2.345207\\\\d = 0.4455 \approx 0.446

Thus the optimum pinhole diameter for a camera box with a length of 10 centimeters is 0.446 mm

6 0
3 years ago
Eight times four is how much less than six squared
andreev551 [17]
8 times four is less than 6 squared by 4, because 8*4 = 32 and 6^2 = 36 then 36-32 = 4. 
8 0
3 years ago
If we divide the numerator and denominator of (6/8) by 2, will its value be changed?
astraxan [27]

Answer:

Step-by-step explanation:

6/8 in simplest form is 3/4 but value is still the same so

1. no

3 0
2 years ago
What is the area of something that is 2 inches long and 5/6 inches wide
Free_Kalibri [48]
Area = Length x Width

The Length is 2 inches
The Width is 5/6 inches

2 * (5/6) = 10/6

simplify and you get....
5/3
5 0
3 years ago
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