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shutvik [7]
3 years ago
8

He solution to the initial value problem x′′+2x′+26x=5cos(4t),x(0)=0,x′(0)=0 x″+2x′+26x=5cos⁡(4t),x(0)=0,x′(0)=0 is the sum of t

he steady periodic solution xspxsp and the transient solution xtrxtr. find both xspxsp and xtrxtr.
Mathematics
1 answer:
ddd [48]3 years ago
3 0
EFSSSSSSSSSSSSSSSSSSSSSSSSSSSSS
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How would you solve
harkovskaia [24]

4r^-3 * 2r^2 =

4*(2r^(-3+2))

= 4*2r^-1

= 4*2(1/r)

= 4*(2/r)

=8/r

4 0
3 years ago
What is the equation of the line that passes through the point (6, 3) and has a slope of -2?
tekilochka [14]

We know the equation of a line is y=mx+b. We know the slope (m) is -2 and all we need is the intercept (b).

Since we know one point, we can plug in 6 for x and 3 for y (along with -2 for m) in our equation and then solve for b.

3= -2*6 + b

3= -12 + b

15 = b

Since we now know the intercept we can now write our equation:

y= -2x + 15

3 0
3 years ago
I need urgent help this in for my final grade
elena-14-01-66 [18.8K]
What is the question?
5 0
3 years ago
Plz hellp this on sum smart peoplw stuff no offence ( you are very smart) :)
scoundrel [369]

Answer:

C)

Step-by-step explanation:

A magician never tells there secret

6 0
3 years ago
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