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shutvik [7]
3 years ago
8

He solution to the initial value problem x′′+2x′+26x=5cos(4t),x(0)=0,x′(0)=0 x″+2x′+26x=5cos⁡(4t),x(0)=0,x′(0)=0 is the sum of t

he steady periodic solution xspxsp and the transient solution xtrxtr. find both xspxsp and xtrxtr.
Mathematics
1 answer:
ddd [48]3 years ago
3 0
EFSSSSSSSSSSSSSSSSSSSSSSSSSSSSS
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14 is the GCF of anumber M and 210. What are possible values of M?
Cloud [144]
<span>14 = GCF of M and 210
M = possible values

GCF = Greatest common denominator
Now, let’s start decomposing
=> 210 | 2
=> 105 | 2
=>  35 | 5
=> 7 | 7
=> 1

Thus, 2 x 3 x 5 x 7 = 210

Now let’s find the factors of 14
=> 14 | 2
=> 7 | 7
=> 1

Thus, 2 x 7 = 14

Notice that’s there’s no 14 in 210 shown factors, but the only GCF found is 7.
Thus, the value of M that we’re looking for is infinite. All numbers that has the GCF of 7 are applicable.</span>



6 0
3 years ago
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6 0
3 years ago
Really need this answered :/ thank you
VladimirAG [237]

Answer:

i believe its the third one don't quote me on that though

Step-by-step explanation:


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What is required in aerobic respiration?<br>​
likoan [24]
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Ainat [17]

Answer:

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