Answer:
The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%
Step-by-step explanation:
Confidence interval for the proportion of people who own a tablet:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
99% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
Percentage:
Multiply the proportion by 100.
0.7159*100 = 71.59%
0.8841*100 = 88.41%
The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%
Answer:
8
Step-by-step explanation:
32/4
Answer:
y = - 9, y = 3
Step-by-step explanation:
Calculate distance d using the distance formula
d = 
with (x₁, y₁ ) = (2, - 3) and (x₂, y₂ ) = (10, y)
d = 
= 
Given distance between points is 10, then
= 10 ( square both sides )
64 + (y + 3)² = 100 ( subtract 64 from both sides )
(y + 3)² = 36 ( take the square root of both sides )
y + 3 = ± 
= ± 6 ( subtract 3 from both sides )
y = - 3 ± 6 , thus
y = - 3 - 6 = - 9
y = - 3 + 6 = 3
Answer:
C = ¼(4B – 7A)
Step-by-step explanation:
⁴/₇(B – C) = A Multiply each side by 7
4(B - C) = 7A Remove parentheses
4B – 4C = 7A Subtract 4B from each side
-4C = 7A – 4B Multiply each side by -1
4C = -7A + 4B Divide each side by 4
C = ¼(4B – 7A)
