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2 years ago

Most linear graphs are direct variation, unless they go through the origin.

1 answer:

5 0

False

A linear graph that is a direct variation is in the form y=kx, so it has a y-intercept at (0,0). This means it passes through the origin if it is a direct variation.

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What is the interquartile range

motikmotik

Answer:

Step-by-step explanation:

Khan academy huh?

put the numbers in order from least to greatest.
find the median
find the difference between the median and all of the other numbers.

P.S. If you were looking for somebody to tell you the answer don't hold your breath.

8 0

3 years ago

Leena bought 14 yards of wire. How many inches of wire did she buy? (1 yard = 36 inches)

lawyer [7]

Answer:

504

Step-by-step explanation:

So, lets calculator this.

For each yard, there are 36 inches.

There are 14 yards.

To find the amount of inches in this 14 yards, we need to multiply 14 by 36:

14x36

504

So there are 504 inches of wire in 14 yards.

Answer:

504

Hope this helps! :)

5 0

3 years ago

Read 2 more answers

Hii giving thanks pls help

olchik [2.2K]

Answer:

x = 52

Step-by-step explanation:

<I = < K b/c of corresponding angles thm

x + 66 + 62 = 180

x + 128 = 180

x = 52

6 0

2 years ago

Let's find2. 1+5 3First write the addition with a common denominator.Then add.12— +51-4-13Х5

emmasim [6.3K]

Answer: $\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}$ Explanation:

The given addition exercise is:

$\frac{2}{5}+\frac{1}{3}$

The LCM of the denominator (5 and 3) = 15

Multiply 2/5 by 3/3

$\frac{2}{5}=\frac{2\times3}{5\times3}=\frac{6}{15}$

Multiply 1/3 by 5/5

$\frac{1}{3}=\frac{1\times5}{3\times5}=\frac{5}{15}$

The addition becomes

$\frac{6}{15}+\frac{5}{15}=\frac{11}{15}$

Therefore, we can fill in the vacant boxes as shown below:

$\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}$

4 0

8 months ago

Find the vertex form of: y=2x^2-5x+13

Ket [755]

The vertex form of a quadratic function is:

f(x) = a(x - h)² + k

The coordinate (h, k) represents a parabola's vertex.

In order to convert a quadratic function in standard form to the vertex form, we can complete the square.

y = 2x² - 5x + 13

Move the constant, 13, to the other side of the equation by subtracting it from both sides of the equation.

y - 13 = 2x² - 5x

Factor out 2 on the right side of the equation.

y - 13 = 2(x² - 2.5x)

Add (b/2)² to both sides of the equation, but remember that since we factored 2 out on the right side of the equation we have to multiply (b/2)² by 2 again on the left side.

y - 13 + 2(2.5/2)² = 2(x² - 2.5x + (2.5/2)²)

y - 13 + 3.125 = 2(x² - 2.5x + 1.5625)

Add the constants on the left and factor the expression on the right to a perfect square.

y - 9.875 = 2(x - 1.25)²

Now, we need y to be by itself again so add 9.875 back to both sides of the equation to move it back to the right side.

y = 2(x - 1.25)² + 9.875

Vertex: (1.25, 9.875)

Solution: y = 2(x - 1.25)² + 9.875

Or if you prefer fractions

y = 2(x - 5/4)² + 79/8

7 0

3 years ago