Answer:
A Quadratic Equation can have upto 2 roots maximum. So,if one of the roots is a Real number, there are following two possibilities:
1) The other root is also a real number, but a different number
2) Its a repeated root, so the other root is the same number.
The other root cannot be a complex number as its not possible for one root to be real and other to be complex. Either no root will be complex or both will be complex roots.
Following are 3 possibilities for the roots of a quadratic equation:
- 2 Real and Distinct roots
- 2 Real and Equal roots
- 2 Complex roots
In a circle, the arc is two times the length of the angle.
EFG = 98°
98 x 2 = 196
Minor arc EG = 196°
Hopefully this helps :)
We are given with two functions: f(x) = x + 8 and g(x) = x2 - 6x - 7. In this problem, the value of f(g(2)) is asked. We first substitute g(x) to f(x) resulting to f(x2 - 6x - 7) = x2 - 6x - 7 + 8 = x2 - 6x + 1. If x is equal to 2, then <span>f(g(2)) = 2^</span>2 - 6*2 + 1 equal to -7.
Answer:
m= 1/7
Step-by-step explanation:
To solve for slope: y2- y1/ x2- x1 so,
1-2/ -2-5
= -1/ -7
= 1/7