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gtnhenbr [62]
3 years ago
13

How would you print from 1 to 1000

Computers and Technology
1 answer:
Hitman42 [59]3 years ago
5 0

Answer:

There are two ways to print 1 to 1000

  1. Using Loops.
  2. Using Recursion.

Explanation:

Using loops

for(int i=1;i<=1000;i++)

{

  cout<<i<<" ";

}

Using recursion

Remember you can implement recursion using a function only.

void print(int n)

{

  if(n==0)

  return;

  print(n-1);

  cout<<n<<" "';

}

you should pass 1000 as an argument to the function print.

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Explanation:

The metropolitan area network connect the user with a geographic area of the size of  metropolitan area.Metropolitan area network connect LAN i.e " local area network " to a single larger network thats provide efficient  connection to the WAN network.Their are many advantage to use metropolitan area network which are mention above .

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tia_tia [17]

The value that x will return when it runs the above loop for the first time is Tom. It is to be noted that the above code is JavaScript.

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A program that accepts insurance policy data, including a policy number, customer last name, customer first name, age, premium d
valentina_108 [34]

Answer:

  1. policy_num = int(input("Enter policy number: "))
  2. lastName = input("Enter last name: ")
  3. firstName = input("Enter first name: ")
  4. premiumDate = input("Enter premius due date (mm/dd/yyyy): ")  
  5. numAcc = int(input("Enter number of driver accident in the past three years: "))
  6. if(policy_num <1000 or policy_num > 9999):
  7.    policy_num = 0  
  8. dateComp = premiumDate.split("/")
  9. month = int(dateComp[0])
  10. day = int(dateComp[1])
  11. year = int(dateComp[2])
  12. if(month < 1 or month > 12):
  13.    month = 0
  14.    day = 0
  15.    year = 0  
  16. else:
  17.    if(month == 1 or month == 3 or month == 5 or month == 7 or month == 8 or month == 10 or month == 12):
  18.        if(day < 1 or day > 31):
  19.            month = 0
  20.            day = 0
  21.            year = 0  
  22.    elif(month == 4 or month == 6 or month == 9 or month == 11):
  23.        if(day <1 or day > 30):
  24.            month = 0
  25.            day = 0
  26.            year = 0
  27.    elif(month == 2):
  28.        if(day < 1 or day > 29):
  29.            month = 0
  30.            day = 0
  31.            year = 0
  32. print("Policy number: " + str(policy_num))
  33. print("Last name: " + lastName)
  34. print("First name: " + firstName)
  35. print("Premium Date: " + str(month) + "/" + str(day) + "/" + str(year))
  36. print("Number of driver accidentin the last three years: " + str(numAcc))

Explanation:

The solution code is written in Python 3.

Firstly use input function to prompt user to enter all the necessary insurance policy data (Line 1 - 5).

Next create an if statement to validate the input policy number. If the policy number is not within the range of 1000 - 9999, set the policy number to zero (Line 7 -8).

Next, split the input premium date into month, day and year (Line 10 -13). It is followed by checking the month if it is between 1 - 12. If not, set the month, day and year to zero (Line 15 - 18). Otherwise the program will proceed to validate the month based on the maximum and minimum number of days for a particular month (Line 20 - 34). If the day is out of range, set month, day and year to zero.

Lastly, use print function to display the policy data (Line 36 - 40).

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