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Doss [256]
3 years ago
9

How many much memory is in one megabyte ?

Computers and Technology
1 answer:
Igoryamba3 years ago
5 0

Answer: 8 bits is a byte. 1000 bytes are a kilobyte. 1000 kilobytes are a megabyte.

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While working alone at their constant rates computer X can process 240 files in 4 hours, and comp Y 240 files in 8 hrs. If all f
djverab [1.8K]

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2hrs 40 min

Explanation:

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Escribe dos diferencias entre las computadoras de la primera y la sexta generacion me pueden ayudar​
Hatshy [7]

Answer:

.N. Generación & Descripción

1

Primera Generación

El período de primera generación: 1946-1959. Base del tubo de vacío.

2

Segunda Generación

El período de la segunda generación: 1959-1965. Base del Transistor

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Tercera generación

El período de tercera generación: 1965-1971. Circuito integrado de base.

4

Cuarta Generación

El período de cuarta generación: 1971-1980. Base del Microprocesador VLSI.

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Quinta Generación

El período de la quinta generación: 1980 en adelante. Base del Microprocesador ULSI.

Explanation:

espero y esto te sirva de algo

3 0
2 years ago
If ADD = 81, BAD = 49, and CAD = 64, then what is the value of ACA?
Digiron [165]

Answer:

its 72

Explanation:

i know it because i did it and thats how i know it

6 0
2 years ago
A retail store stocks two types of shirts A and B. These are packed in attractive cardboard boxes. During a week the store can s
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Write a program that will read in a line of text and output the number of words in the line and the number of occurrences of eac
kherson [118]

Answer:

Here is the C++ program:

#include<iostream>  //to use input output functions

#include <algorithm>  //to use tolower() function

using namespace std;  //to identify objects like cin cout

int main() {  //start of main function

 string text;  // to hold text input

 cout<<"Enter a line of text: ";  // prompts user to enter a string

 getline(cin,text);  // reads the input string (text) from user

transform(text.begin(), text.end(), text.begin(), ::tolower);  //converts the text into lower case

 int letter[26] = {0}; //to hold the letters

 int i;  // used as a loop variable

 int words=0;  // to hold the count of words

 for(i = 0; i< text.size();i++){  // iterates through the text

 if(isalpha(text[i])&&(text[i+1]=='.'||text[i+1]==','||text[i+1]==' '))  //checks if the character at i-th index of text is a letter, and checks if i+1 index position of text is a period, comma or a space

 words++;  // adds 1 to the count of words

 if(isalpha(text[i]))  // if the character at the i-th index of text is a letter

 letter[text[i]-'a']++;  }  // counts the occurrences of each letter

 char j = text[text.size()-1];  // sets j to the last character of text

 if(j != '.' && j!= ' '&& j!=',' &&j!= '\0')  //if the last character is not a period or empty space  or comma or end of lone

 words++;  //add 1 to the count of words

 cout<<"Number of words: "<<words<<endl;  //display the number of words in the text

 for(i=0; i<26; i++)  {  //iterates 25 times

   if(letter[i]>0)  //if letter at index i is greater than 0

   cout<<(char)('a'+i)<<" : "<<letter[i]<<endl;  }} //displays each letters and its number of occurrences in the text

 

Explanation:

The program is explained in the attached document with an example.

7 0
3 years ago
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