Answer:
A= –65/81
Step-by-step explanation:
hope this explains it
Given :
Area of rectangle.
To Find :
The dimensions of a rectangle (in m) with area 1,728 m2 whose perimeter is as small as possible.
Solution :
Let, the dimensions of rectangle is x and y.
Area, A = xy.
x = A/y. ....1)
Perimeter, P = 2( x + y )
Putting value of x in above equation, we get :

For minimum P,

SO, it is a square.

Therefore, the dimensions are
.24\sqrt{3}
Hence, this is the required solution.
Answer:
The correct answers is rectangle and square.
P(x) = 25^2 -24x + 615
P(8) = 25(8 squared) -24(8) +615 = 2023
Answer:
-6
Step-by-step explanation:
next step is
-10 +4
you move the 4 to the other side
that equals -6