Answer:
I think it would be 34 because I divided 68.2 by 4 and got 17.05, so I multiplied that by 2, and it's closest to 34.
<em>So I think it's A.</em>
But y'all don't be mad if I'm wrong cuz I said I think.
They are a part of 2 dozen
Answer:
1. 41/45.
2. x/(x^2+3x+6)
Step-by-step explanation:
1.
So first we fill the ven diagram.
There are 240 in band, so we fill that. 60 students are in both, we put that in the middle, and there are 110 people in choir.
now, since we want the probability that a student is chosen that is in band, and choir, and both. We add all this up
240 + 60 + 110 = 410.
The total possible outcome is 410, and the total outcome is 450, so the answer is
410/450 = 41/45
2.
First, to get the total outcomes, we have to add all the expressions together.
x(x-2) + x + 2x+8 = x^2 - 2 + x + 2x + 8 = x^2 - 2 + 3x + 8 = x^2 + 3x + 6.
Since that is the total outcome, we have to find the possible outcomes.
The problem wants BOTH from the 20th century and British, so it is x.
x/(x^2+3x+6). We cannot simplify any further, thus x/(x^2+3x+6) is our answer
1/6 a cup. Since she was supposed to use 1/2 a cup for the original, just divide that by three and it’s 1/6
<span>In
the given number : 4 083 817. Find the 3 digit which is placed in the unit
period.
=> The unit period is the digit that is placed in the ones place of the
number or the first digit on the right.
=> 7 is the unit period
=> 3 is the another unit period
=> 4 is the another unit period.
Thus, 4, 3 and 7 are the 3 digits placed in the unit period of the given
number.</span><span>
</span>
