The answer to the problem de

My calculator does not have a 3 key that works! How can I use this broken calculator to do 23 x 45.

erik [133]

<h3><u>Solution:-</u></h3>

$\longrightarrow$ This problem can be tackled by using distributive property of multiplication .

It states for any three numbers a,b and c

$\green{ \underline { \boxed{ \sf{(a±b)\times c = a \times c±b\times c}}}}$

<u>Similarly</u>,

$\quad$ 23 × 45

$\longrightarrow$ (21+2) ×45

$\longrightarrow$ 21×45+2×45

$\longrightarrow$ 945 + 90

$\longrightarrow$ 1035

It can also be done as-

$\quad$ 23 × 45

$\longrightarrow$ (25-2) ×45

$\longrightarrow$ 25×45-2×45

$\longrightarrow$ 1125-90

$\longrightarrow$ 1035

3 0

2 years ago

M is the incenter of triangle ABC. Find the lengths of MD and DC. (Look at pic)

Deffense [45]

Answer:

Part 1) $MD=9\ units$

Part 2) $DC=12\ units$

Step-by-step explanation:

Step 1

Find the length of MD

we know that

The incenter is the intersection of the angle bisectors of the three vertices of the triangle. Is the point forming the origin of a circle inscribed inside the triangle

so

In this problem

$MD=ME=MF$ ------> is the radius of a circle inscribed inside the triangle

we have that

$MF=9\ units$

therefore

$ME=9\ units$

$MD=9\ units$

Step 2

Find the length of DC

we know that

In the right triangle MDC

Applying the Pythagoras theorem

$MC^{2} =MD^{2}+DC^{2}$

we have

$MD=9\ units$

$MC=15\ units$

substitute

$15^{2} =9^{2}+DC^{2}$

$DC^{2}=225-81$

$DC=\sqrt{144}\ units$

$DC=12\ units$

6 0

4 years ago

What's the answer?<br> Cuz I'm really stuck

Tju [1.3M]

(5*10000)^2

510000^2

260100000000

or 250*10^8

7 0

4 years ago

You are making a necklace that is 9 inches long. You use 6 needs for each inch. What integer is the change in your supply of bea

zaharov [31]

6 x 9 is how many beads you need to use.

4 0

3 years ago

Perform a one-proportion z-test for a population proportion. Be sure to state the hypotheses and the P-Value. State your conclus

emmainna [20.7K]

Answer:

There is not enough statistical evidence in the sample taken by the veterinarian to support his skepticism

Step-by-step explanation:

To solve this problem, we run a hypothesis test about the population proportion.

Proportion in the null hypothesis $\pi_0 = 0.37$

Sample size $n = 150$

Sample proportion $p = 54/150 = 0.36$

Significance level $\alpha = 0.05$

$H_0: \pi_0 = 0.36\\H_a: \pi_0$

Test statistic $= \frac{(p - \pi_0)\sqrt{n}}{\sqrt{\pi_0(1-\pi_0)}}$

Left critical Z value (for 0.01) $Z_{\alpha/2}= -1.64485$

Calculated statistic = $= \frac{(0.36 - 0.37)\sqrt{150}}{\sqrt{0.37(0.63)}} = -0.254$

$p-value = 0.6003$

Since, test statistic is greater than critical Z, the null hypothesis cannot be rejected. There is not enough statistical evidence to state that the true proportion of pet owners who talk on the phone with their pets is less than 37%. The p - value is 0.79860.

4 0

3 years ago