Hello!
If we want to find the mean (average) of any set of numbers, all you need to do is add the set together, then divide by how many numbers are in the set.
When we add all the numbers we get: 100
Next we just divide by the number of people which is 10: 100 divided by 10 is 10
So, the mean age of the swimmers on the team is an even number of 10.
Does that mean solve for y? If so, here it is:
5x + 2y = 11.
Move the x term by subtracting.
2y = -5x + 11
Divide by 2.
y = -5/2x + 11/2
Answer:
r = 3
Step-by-step explanation:
x^2 + 6x + y^2 - 8y = - 16
Take half the linear term and square it.
x^2 + 6x + (3)^2 + y^2 - 8y + (-4)^2 = - 16
Add the squared amounts to the right.
x^2 + 6x + 9 + y^2 - 8y + 16 = - 16 + 9 + 16
Combine on the right.
x^2 + 6x + 9 + y^2 - 8y + 16 = 9
Represent the 2 quadratics as perfect squares.
(x + 3)^2 + y - 4)^2 = 9
The radius is the square root of 9 which is 3
ARea = area of square + area of semicircle
= 26^2 + 0.5pi(13)^2
= 941.46 square inches to nearest hundredth
Let x = number of adult tickets sold
Let x-53 = number of student tickets sold
x + x -53 = 697
2x - 53 = 697.
Add 53 to both sides to get:
2x = 750
Divide both sides by 2 to get:
x = 375
375 adult tickets were sold.
