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AleksAgata [21]
2 years ago
13

Can someone please help me it's worth five points

Mathematics
1 answer:
Brilliant_brown [7]2 years ago
7 0

The formula of a volume of a cone:

V=\dfrac{1}{3}Bh=\dfrac{1}{3}\pi r^2h

We have:

r=12cm,\ h=8cm

Substitute:

V=\dfrac{1}{3}\pi\cdot12^2\cdot8=\dfrac{1}{3}\pi\cdot144\cdot8=\pi\cdot48\cdot8=384\pi\ cm^2\approx384\cdot3.14=1205.76\ cm^3\approx1206\ cm^3

Answer: 1206 cm³

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Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N(\mu = 7 lbs , \sigma^{2}  = 0.875^{2}  lbs)

The standard normal z distribution is given by;

              Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean weight

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Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{7.5-7}{\frac{0.875}{\sqrt{4} } }  ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

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Step-by-step explanation:

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