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kobusy [5.1K]
3 years ago
7

2. The area of a square is represented by the expression 16m2 - 40m + 25 square units. write the expression to represent the dim

ensions for each side. Explain what process you use. Justify your answer.
​
Mathematics
2 answers:
tester [92]3 years ago
8 0

Answer:

Each side = 4m-5

Step-by-step explanation:

16m2 - 40m + 25

factor:

(4m - 5)(4m - 5)

Each side = 4m-5

leva [86]3 years ago
5 0

Answer:

The expression for each side = 4m - 5.

Step-by-step explanation:

We need to factor the expression for the area. As the figure is a square both factors should be identical.

16m^2 - 40m + 25:

16m^2 and 25 are both perfect squares so looks like the factors are

(4m - 5)(4m - 5)

The signs are negative because the middle term is - 40m.

If we expand the factors we get:

4m*4m - 5*4m - 5*4m -5*-5

16m^2 - 20m - 20m + 25

= 16m^2 - 40m + 25  which is the original expression, so this confirms our result.

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PLEAZE HELP IM FAILING THIS CLASS 9) The volume of a box is represented by x' +11x² + 20x – 32. The width of the box is x – 1, a
In-s [12.5K]

Answer:

Step-by-step explanation:

Volume of the box  =  x³ +11x² + 20x – 32        I think the ' is a typo for ³

      the width is x-1    and the height is x+8      

Find an expression for the length

       Vol = LWH    solve L

        Vol / (WH)   =  L     so

L  =  (x³ +11x² + 20x – 32) / (x-1) (x+8)      

                    so it would help to factor the numerator

       (x³ +11x² + 20x – 32)       I'm willing to bet (x-1) and  (x+8) are factors

                                               but I will plot the equation to find the three roots

        (x³ +11x² + 20x – 32)  = (x-1) (x+8) (x+4)

L  =  (x³ +11x² + 20x – 32) / (x-1) (x+8)

   =  (x-1) (x+8) (x+4) / (x-1) (x+8)           the (x-1) and (x+8) cancel out leaving

L =   (x + 4)

7 0
3 years ago
In relation t a functions? Is the inverse of relation t function
frozen [14]

Answer:

Relation t is a function. The inverse of relation t is not a function ⇒ 3rd

Step-by-step explanation:

* Lets explain how to solve the problem

- A relation is a set of inputs and outputs, and a function is a relation

 with one output for each input

- Ex: T = {(1 , 2) , (3 , 5) , (-4 , 0)} is a function because every input has

  only one output

- To find the inverse of a function we switched the input and the

  out put

- The inverse of a function may not always be a function

* Lets solve the problem

∵ The relation t is the set of ordered pairs of x and y

  x = 0     2      4    6

  y = -8    -7    -4    -4

∵ x = 0 has only y = -8

∵ x = 2 has only y = -7

∵ x = 4 has only y = -4

∵ x = 6 has only y = -4

∴ Every value of x has only one value of y

∴ Relation t is a function

* Lets find its inverse by switching x and y

∵ The inverse function of t is :

   x = -8     -7     -4    -4

   y =  0      2      4     6

∵ x = -8 has only y = 0

∵ x = -7 has only y = 2

∵ x = -4 has y = 4 and y = 6

∴ Not every value of x has only one value of y

∴ The inverse of relation t is not a function

* Relation t is a function. The inverse of relation t is not a function

4 0
2 years ago
Please help.<br> Explain please.
Sunny_sXe [5.5K]
When n = 1, 2(1) + 1 = 3

When n = 2, 2(2) + 1 = 5

When n = 3, 2(3) + 1 = 7

When n = 4, 2(4) + 1 = 9

When n = 5, 2(5) + 1 = 11

Sum = 3 + 5 + 7 + 9 + 11 = 35

----------------------------------------------------
Answer: 35
----------------------------------------------------
4 0
3 years ago
Read 2 more answers
Somebody help me out with this one and explain how u got it I will mark u as brainiest if correct
timofeeve [1]

Answer:

C.

Step-by-step explanation: im pretty sure because if you look at Ed its 5 and then if you add the same sides twice its 10 hopefully im right

7 0
2 years ago
Graph (1,1), (1,2), (1,3), (1,4)
jenyasd209 [6]

Answer:

There is not a way that I can show you how to graph it, so I will try and explain it.

Step-by-step explanation:

(1,1)

^  ^     y-axis

x-axis

You are just going right however many, and then up however many it says.

So if it's (1,1) you will go right one space, and then up one space.

Once you have all of your points on the graph, you put a line through them.

Hope this helps! :)

3 0
2 years ago
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