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f(g(x))=362−x−2k f(g(x))=x→362−x−2k=x→x2−2x(1−k)−4(k−9)=0 Solution for x are equal if and only if discriminant Δ=0 4(1−k)2+16(k−9)=0 ... More
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is it from a text book
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123445
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125123254125
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area = ‐11
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hope this is correct and helps
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um ight if your asking me if there are right i guess they are...
